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Orlov [11]
3 years ago
10

The last one was cut off, please help

Mathematics
2 answers:
siniylev [52]3 years ago
8 0

Answer:

5 days

Step-by-step explanation:

plan A for 5 days = 30*5 = 150

plan B for 5 days = 25*5 + 15 = 140

shepuryov [24]3 years ago
8 0
The answer would be 5 or D
You might be interested in
2 ÷ ___ = 4<br> A) 0.5 <br> B) 0.05 <br> C) 4 <br> D) 0.4
olga nikolaevna [1]
Heya!

2/0.5=4

You can check your work by multiplying 0.5*4.
3 0
3 years ago
Give a geometric description of the following system of equations.a. 2x−4y=12 −3x+6y=−15.b. 2x−4y=12 −5x+3y=10.a. 2x−4y=12 −3x+6
Reptile [31]

Answer:

a. No solution, parallel lines.

b. One solution.

Step-by-step explanation:

Given the system of equations:

a. 2x-4y=12

-3x+6y=-15

b. 2x-4y=12

-5x+3y=10

To give a geometric description of the given system of equations.

The geometric description of a system of equations in 2 variables mean the system of equations will represent the number of lines equal to the number of equations in the system given.

i.e.

Number of planes = Number of variables

Number of lines = Number of equations in the system.

Here, we are given 2 variables and 2 equation in each system.

So, they can be represented in the xy-coordinates plane.

And the number of solutions to the system depends on the following condition.

Let the system of equations be:

A_1x+B_1y+C_1=0\\A_2x+B_2y+C_2=0

1. One solution:

There will be one solution to the system of equations,  If we have:

\dfrac{A_1}{A_2}\neq\dfrac{B_1}{B_2}

2. Infinitely Many Solutions: (Identical lines in the system)

\dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}= \dfrac{C_1}{C_2}

3. No Solution:(Parallel lines)

\dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}\neq\dfrac{C_1}{C_2}

Now, let us discuss the system of equations one by one:

a. 2x-4y=12 OR 2x-4y-12=0

-3x+6y=-15 OR -3x+6y+15=0

A_1 = 2, B_1 = -4, C_1 = -12\\A_2 = -3, B_2 = 6, C_2= 15

Here, the ratio:

\dfrac{A_1}{A_2}=\dfrac{B_1}{B_2} = -\dfrac{2}{3}\\\dfrac{C_1}{C_2} = -\dfrac{4}{5}

\dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}\neq\dfrac{C_1}{C_2}

Therefore, no solution i.e. parallel lines.

b. 2x-4y=12 OR 2x-4y-12=0

-5x+3y=10 OR -5x+3y-10=0

A_1 = 2, B_1 = -4, C_1 = -12\\A_2 = -5, B_2 = 3, C_2 = -10

\dfrac{A_1}{A_2}= -\dfrac{2}{5}\\\dfrac{B_1}{B_2} = -\dfrac{4}{3}\\\dfrac{C_1}{C_2} = -\dfrac{6}{5}

\dfrac{A_1}{A_2}\neq\dfrac{B_1}{B_2}

So, one solution.

Kindly refer to the images attached for the graphical representation of the given system of equations.

6 0
3 years ago
HELP ASAP DUE TODAY
mrs_skeptik [129]
I think the answer is sas
4 0
3 years ago
Which equation would you use to solve this problem?
const2013 [10]
I have no idea what is is but try 4 or 1,If not you should go on cymath
8 0
3 years ago
Read 2 more answers
Factorise the expression 4(x+1)^2-49 . plz solve this i will mark you the brainliest
Vinil7 [7]

Answer:The answer is : Expand the square

4(x+1)the second square - 49

4(x+1)x+1)-49

The solution is : 4x second square + 8x - 45

Step-by-step explanation:

5 0
3 years ago
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