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monitta
3 years ago
12

In the diagram of △EHG below, JF ∥HG, EJ=12, JH=24, and EF=6. What is the length of EG?

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
4 0
It’s 18, i guess
FG = JHxEF/EJ = 12 + 6 = 18
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