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Alina [70]
3 years ago
7

The high point on a wave is called its _________

Physics
2 answers:
Nataly [62]3 years ago
8 0

Answer:

I believe its called the crest

Explanation:

sweet-ann [11.9K]3 years ago
8 0

Answer:

crest

Explanation:

the highest surface is called crest. the lowest is the trough. the vertical distance between the crest and trough is the wave height. the horizontal distance between two adjacent crests or troughs is known as the wavelength.

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The loudness of a sound is determined by the __________, or height, of the sound wave.
NISA [10]

Answer: Aplitude

Explanation: Loudness depends on the amplitude,or height, of sound waves. The greater the amplitude, the louder the sound perceived. Amplitude is measured in decibels.

4 0
3 years ago
What is element ratio?
kenny6666 [7]

Answer:

A ratio is a way to compare quantities of things.

Explanation:

by dividing the number of moles of each by the smallest number of moles.

3 0
3 years ago
Problem: The circular blad on a radial arm saw is turning at262
kobusy [5.1K]

Answer:

Net torque, \tau=-0.033\ N-m

Explanation:

It is given that,

Initial angular speed of the blade, \omega_i=262\ rad/s

Final angular speed of the blade, \omega_f=85\ rad/s

Time, t = 18 s

Radius of the disk, r = 0.13 m

Mass of the disk, m = 0.4 kg

We need to find the net torque applied to the blade. We know that in rotational mechanics the net torque acting on an object is equal to the product of moment of inertia and the angular acceleration such that,

\tau=I\times \alpha

The moment of inertia of the disk, I=\dfrac{mr^2}{2}

\tau=\dfrac{mr^2}{2}\times \dfrac{\omega_f-\omega_i}{t}

\tau=\dfrac{0.4\times (0.13)^2}{2}\times \dfrac{85-262}{18}

\tau=-0.033\ N-m

Negative sign shows that the net torque is acting in the opposite direction of its motion. Hence, this is the required solution.

3 0
3 years ago
What is the most common way to organize data in a experiment
kobusy [5.1K]

A chart because you can set it up anyway you want

5 0
4 years ago
what is the efficiency of a machine that can carry a load of 100 kg with an effort of 20N when its velicity ratio is 10​ ASAP
Salsk061 [2.6K]

Answer:

Efficiency of machine=4.9

Explanation:

We are given that

Mass of load=100 kg

Effort=20 N

Velocity ratio=10

We have to find the efficiency of machine.

Load=mg=100\times 9.8=980 N

Efficiency=\frac{Load}{effort}\times \frac{1}{velocity\;ratio}

Using the formula

Efficiency of machine=\frac{980}{20}\times \frac{1}{10}

Efficiency of machine=\frac{49}{10}

Efficiency of machine=4.9

7 0
4 years ago
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