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Elenna [48]
3 years ago
5

What would be some benefits of living on a planet with less surface gravity

Physics
2 answers:
Ket [755]3 years ago
4 0
This is a tricky one.

-- IF I evolved on that planet, then my body is perfectly matched to the
conditions and the environment over there, and I am approximately just
as happy and care-free la de da over there as I really am on Earth,
and I can't imagine living anywhere else.

-- IF I evolved on Earth, and I move this body to a planet with less
surface gravity, then there are all kinds of complications.

. . . Even if the atmosphere over there has the same gases in the
same ratios as Earth's atmosphere, the lower gravity means that the
atmosphere has lower weight.  In turn, that means that the surface
pressure is lower, and I have to work harder to take in enough oxygen to
keep my Earth body functioning.  Breathing alone could be a full-time job.

. . . The acceleration of gravity is less than 9.8 m/s² over there.
This means that when I drop something, it falls slower than I'm used to,
and I can usually grab it before it hits the floor.
When I lift something with the normal force of my Earth arm, it jumps up
faster than I expect.  Until I get used to things, I'll probably overshoot,
lift things too high and too fast, maybe spill the coffee etc.

. . . With my Earth muscles, almost everything takes less force. 
It's a lot easier to walk around.  I bob up and down more than usual,
and my steps are longer.  When I run, it's really funny.  Every time
I take a step, I sail several feet into the air, and come down farther
than I ever did, but it all happens in slow motion.

All of this is fun while it lasts, but it doesn't last long.  My Earth body
gets adjusted to the new planet.  Before long, I actually lose muscle mass
AND bone, so that if I were to go back to Earth, I would be so weak that
I'd have to be carried around for a while.

We know this from what happens to the astronauts who spend 6 months
or a year in zero G on the International Space Station.  Even when they
do resistance exercises for an hour a day, they come back with less
muscle strength and less bone mass.
zepelin [54]3 years ago
3 0
You could jump high!
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A plastic bag is massed. It is then filled with a gas which is insoluble in water and massed again. The apparent weight of the g
levacccp [35]

The actual weight of the gas = apparent weight + weight.

The actual weight = W_{A} + W

Given that a plastic bag is massed. It is then filled with a gas which is insoluble in water and massed again.

If the apparent weight of the gas is the difference between these two masses, then let the apparent weight = W_{A}

The gas is squeezed out of the bag to determine its volume by the displacement of water. Since

density = mass / volume

The density of water is 1000 kg/m^{2}

we can get the mass of the gas by making m the subject of the formula.

W = mg

The actual weight of the gas = apparent weight + weight

That is,

The actual weight =  W_{A} + W

Learn more about density here: brainly.com/question/406690

8 0
2 years ago
To balance the forces on the box what direction must you push?
ss7ja [257]
The correct answer would be left
3 0
3 years ago
A 10 gauge copper wire carries a current of 20 A. Assuming one free electron per copper atom, calculate the magnitude of the dri
nordsb [41]

Complete Question

A 10 gauge copper wire carries a current of 20 A. Assuming one free electron per copper atom, calculate the drift velocity of the electrons. (The cross-sectional area of a 10-gauge wire is 5.261 mm2.) mm/s

Answer:

The drift velocity is v  = 0.0002808 \ m/s

Explanation:

From the question we are told that

    The current on the copper is  I  = 20 \ A

     The cross-sectional area is  A =  5.261 \ mm^2 =  5.261 *10^{-6} \ m^2

The number of copper atom in the wire is  mathematically evaluated

      n  =  \frac{\rho *  N_a}Z}

Where \rho is the density of copper with a value \rho =  8.93 \ g/m^3

          N_a is the Avogadro's number with a value N_a  = 6.02 *10^{23}\ atom/mol

         Z  is the molar mass of copper with a value  Z =  63.55 \ g/mol

So

     n  =  \frac{8.93 * 6.02 *10^{23}}{63.55}

     n  = 8.46 * 10^{28}  \  atoms /m^3

Given the 1 atom is equivalent to 1 free electron then the number of free electron is  

         N  = 8.46 * 10^{28}  \  electrons

The current through the wire is mathematically represented as

         I  =  N * e * v * A

substituting values

        20 =  8.46 *10^{28} * (1.60*10^{-19}) * v *  5.261 *10^{-6}

=>     v  = 0.0002808 \ m/s

       

8 0
3 years ago
WHAT DOES DENSITY HAVE TO DO WITH PLATE TECTONICS?<br> Explain
Korvikt [17]

Answer: The reason for the differences in density is the composition of rock in the plates. When two plates come in contact with each other through plate tectonics, scientists can use the density of the plates to predict what will happen. Whichever plate is more dense will sink, and the less dense plate will float over it.

Explanation:

Hope this helps ( not copied and pasted, this answer was done by me so I don't know if it's good or not)

5 0
3 years ago
Dona rolls a marble with a speed of 5.0/m/s across a level table that is 1.6m above the floor. Upon reaching the edge of the tab
san4es73 [151]

Answer:

2.9 m

Explanation:

First find the time it takes to reach the floor.

y = y₀ + v₀ t + ½ at²

(0 m) = (1.6 m) + (0 m/s) t + ½ (-9.8 m/s²) t²

t = 0.571 s

Next, find the distance it travels in that time.

x = x₀ + v₀ t + ½ at²

x = (0 m) + (5.0 m/s) (0.571 s) + ½ (0 m/s²) (0.571 s)²

x = 2.86 m

Rounded to two significant figures, the marble travels 2.9 meters in the x direction.

5 0
3 years ago
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