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3 years ago

What would be some benefits of living on a planet with less surface gravity

2 answers:

4 0

This is a tricky one.

-- IF I evolved on that planet, then my body is perfectly matched to the
conditions and the environment over there, and I am approximately just
as happy and care-free la de da over there as I really am on Earth,
and I can't imagine living anywhere else.

-- IF I evolved on Earth, and I move this body to a planet with less
surface gravity, then there are all kinds of complications.

. . . Even if the atmosphere over there has the same gases in the
same ratios as Earth's atmosphere, the lower gravity means that the
atmosphere has lower weight. In turn, that means that the surface
pressure is lower, and I have to work harder to take in enough oxygen to
keep my Earth body functioning. Breathing alone could be a full-time job.

. . . The acceleration of gravity is less than 9.8 m/s² over there.
This means that when I drop something, it falls slower than I'm used to,
and I can usually grab it before it hits the floor.
When I lift something with the normal force of my Earth arm, it jumps up
faster than I expect. Until I get used to things, I'll probably overshoot,
lift things too high and too fast, maybe spill the coffee etc.

. . . With my Earth muscles, almost everything takes less force.
It's a lot easier to walk around. I bob up and down more than usual,
and my steps are longer. When I run, it's really funny. Every time
I take a step, I sail several feet into the air, and come down farther
than I ever did, but it all happens in slow motion.

All of this is fun while it lasts, but it doesn't last long. My Earth body
gets adjusted to the new planet. Before long, I actually lose muscle mass
AND bone, so that if I were to go back to Earth, I would be so weak that
I'd have to be carried around for a while.

We know this from what happens to the astronauts who spend 6 months
or a year in zero G on the International Space Station. Even when they
do resistance exercises for an hour a day, they come back with less
muscle strength and less bone mass.

zepelin [54]3 years ago

3 0

You could jump high!

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Most automobiles have a coolant reservoir to catch radiator fluid that may overflow when the engine is hot. A radiator is made o

Colt1911 [192]

Answer:

There is a loss of fluid in the container of 0.475L

Explanation:

To solve the problem it is necessary to take into account the concepts related to the change of voumen in a substance depending on the temperature.

The formula that describes this thermal expansion process is given by:

$\Delta V = \beta V_0 \Delta T$

Where,

$\Delta V =$ Change in volume

$V_0 =$ Initial Volume

$\Delta T =$ Change in temperature

$\beta =$ coefficient of volume expansion (Coefficient of copper and of the liquid for this case)

There are two types of materials in the container, liquid and copper, so we have to change the amount of Total Volume that would be subject to,

$\Delta V_T = \Delta V_l - \Delta V_c$

Where,

$\Delta V_l$ = Change in the volume of liquid

$\Delta V_c$ = Change in the volume of copper

Then replacing with the previous equation we have:

$\Delta V = \beta_l V_0 \Delta T- \beta_c V_0 \Delta T$

$\Delta V = (\beta_l-\beta_c)V_0\Delta T$

Our values are given as,

Thermal expansion coefficient for copper and the liquid to 20°C is

$\beta_c = 51*10^{-6}/\°C$

$\beta_l = 400*10^{-6}/\°C$

$V_0 = 16L$

$\Delta T = (95\°C-10\°C)$

Replacing we have that,

$\Delta V = (\beta_l-\beta_c)V_0\Delta T$

$\Delta V = (400*10^{-6}/\°C-51*10^{-6}/\°C)(16L)(95\°C-10\°C)$

$\Delta V = 0.475L$

Therefore there is a loss of fluid in the container of 0.475L

6 0

3 years ago

Two billiard balls move toward each other on a table. The mass of the number three ball, m1, is 5 g with a velocity of 3 m/s. Th

Ymorist [56]

This question involves the concepts of the law of conservation of momentum and velocity.

The velocity of the eight ball is "5.7 m/s".

According to the law of conservation of momentum:

$m_1u_1+m_2u_2=m_1v_1+m_2v_2$

where,

m₁ = mass of number three ball = 5 g

m₂ = mass of the eight ball = 6 g

u₁ = velocity of the number three ball = 3 m/s

u₂ = velocity of the eight ball = - 1 m/s (negative sign due to opposite direction)

v₁ = final velocity of the three number ball = - 5 m/s

v₂ = final velocity of the eight ball = ?

Therefore,

(5 g)(3 m/s) + (6 g)(- 1 m/s) = (5 g)(- 5 m/s) + (6 g)(v₂)

$v_2=\frac{34\ g.m/s}{6\ g}\\\\$

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Learn more about the law of conservation of momentum here:

brainly.com/question/1113396?referrer=searchResults

4 0

3 years ago

How would you go about separating the components of a mixture of sand, gravel, salt and iron filings

larisa86 [58]

Pour the entire components into water.

First the iron filings can be separated using a magnet as iron is a magnetic element.

By pouring the mixture into water, it allows the salt to dissolve in the water, while the sand will not.

Next we can run this solution through a filtration device to separate the sand from the water.

Now all that's left is to let the water evaporate so that the salt will be exposed that dissolved into the water.

4 0

3 years ago

A common physics demonstration is to drop a small magnet down a long, vertical aluminum pipe. Describe the motion of the magnet

Rzqust [24]

Answer and Explanation:

This experiment is known as Lenz's tube.

The Lenz tube is an experiment that shows how you can brake a magnetic dipole that goes down a tube that conducts electric current. The magnet, when falling, along with its magnetic field, will generate variations in the magnetic field flux within the tube. These variations create an emf induced according to Faraday's Law:

$\varepsilon =-\frac{d\phi_B}{dt}$

This emf induced on the surface of the tube generates a current within it according to Ohm's Law:

$V=IR$

This emf and current oppose the flux change, therefore a field will be produced in such a direction that the magnet is repelled from below and is attracted from above. The magnitude of the flux at the bottom of the magnet increases from the point of view of the tube, and at the top it decreases. Therefore, two "magnets" are generated under and above the dipole, which repel it below and attract above. Finally, the dipole feels a force in the opposite direction to the direction of fall, therefore it falls with less speed.