For this case we have a factorized quadratic equation. We equal each factor to zero and thus find the roots:

Subtracting 5 from both sides we have:

Thus, the first solution of the equation is:

On the other hand we have:

Adding 3 to both sides:

Thus, the second solution of the equation is:

Answer:
The solutions of the equation are:

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X²-9x=36
minus 36 both sides
x²-9x-36=0
what 2 numbers multiply to -36 and add to -9
-12 and 3
(x-12)(x+3)=0
set to zero
x-12=0
x=12
x+3=0
x=-3
the number is either -3 or 12
Answer:
9r²(r - 8)
Step-by-step explanation:
Step 1: Write expression
9r³ - 72r²
Step 2: Factor out 9
9(r³ - 8r²)
Step 3: Factor out r²
9r²(r - 8)
Answer:
3 and 2 r equivalent i belive