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monitta
3 years ago
13

Tickets to the school play cost $4.50 for adults and $3.00 for students. One night 325 tickets where sold and 1140 was collected

. How many of each type was sold?
Mathematics
2 answers:
algol133 years ago
8 0
4.50x+3x=1140
You will add 4.50 and 3 together to get 7.5.
your equation is now...
7.50x=1140
you divide by 7.5 and get 152. so x= 152.
I am stuck now.
alexandr1967 [171]3 years ago
8 0

Answer not here

Step-by-step explanation:

noot here wither

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Katyanochek1 [597]

There is no image but I would likely be glad to help! :)

4 0
3 years ago
In triangle JKL, sin(b°) = three fifths and cos(b°) = four fifths. If triangle JKL is dilated by a scale factor of 2, what is ta
scoundrel [369]

Answer:

Tan(b°) = 3/4 = three fourths (C)

Step-by-step explanation:

Triangle JKL is a right angled triangle in which angle K is a right angle and angle L= b°

We would apply SOHCAHTOA from trigonometry to determine the value for each sides.

For ∆JKL

Sin(b°) = opposite/hypotenuse

Sin(b°) = 3/5

Cos(b°) = adjacent/hypotenuse

Cos(b°) = 4/5

Tan(b°) = 3/4

From the above we know the value of each sides of ∆JKL

Find attached the diagram of the above triangle (1)

∆JKL is dilated by a scale factor = 2

Meaning we would multiply each sides of ∆JKL by 2. The values of the new triangle become:

Opposite = 2(3) = 6

Adjacent = 2(4) = 8

Hypotenuse = 2(5) = 10

To find tan(b°) of the new triangle, we would apply tangent ratio

Tan(b°) = opposite/adjacent

Tan(b°) = 6/8

Tan(b°) = 3/4

Find attached the diagram for the new triangle (2)

Diagram 3 shows the drawing of both triangles together.

From the above, we can see the angle doesn't change when a shape is dilated by a scale factor.

Therefore, tan(b°) = three fourths (C)

6 0
3 years ago
Pretty pls help me with A and B with work SHOWN
-BARSIC- [3]
A.  11/30 x 50= 18/36=1/2

18/36 x 1/10= 5/100

B.    1,210 x 1.1= 1,331

I am not so sure about A, but I hope this helps a little.
7 0
3 years ago
A bug is moving back and forth on a straight path. The velocity of the bug is given by vt=t2-3t. Find the average acceleration o
g100num [7]

Answer:

2 unit/time²

Step-by-step explanation:

Given the equation:

v(t) =t^2-3t

At interval ; 1, 4

V(1) = 1^2 - 3(1)

V(1) = 1 - 3

V(1) = - 2

At t = 4

V(4) = 4^2 - 3(4)

V(4) = 16 - 12

V(4) = 4

Average acceleration : (final - Initial Velocity) / change in time

Average acceleration = (4 - (-2)) ÷ (4 - 1)

Average acceleration = (4 + 2) / 3

Average acceleration = 6 /3

Average acceleration = 2

3 0
3 years ago
15-<br><br><br> pls help!!!!<br><br><br><br> math<br><br> pls help answer other questions<br> too
ddd [48]

Answer:

A

Step-by-step explanation:

The projection of vector B on unit vector a is

(B•a)a

av(unit vector of v)= 1/√2(-1,1)

u•av= 1/√2 × (-5+7)= √2

(u•av)av= √2 × 1/√2(-1,1)= (-1,1)

3 0
2 years ago
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