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solmaris [256]
3 years ago
7

What happens to the average kinetic energy of the particles in a sample of matter as the temperature of the sample is increased?

Chemistry
1 answer:
antiseptic1488 [7]3 years ago
7 0

Answer:

  • <em>As the temperature of a sample of matter is increased, the average kinetic energy of the particles in the sample </em><u>increase</u><em>.</em>

Explanation:

The <em>temperature</em> of a substance is the measure of the <em>average kinetic energy </em>of its partilces.

The temperature, i.e. how hot or cold is a substance, is the result of the collisions of the particles (atoms or molecules) of matter.

The kinetic theory of gases states that, if the temperature is the same, the average kinetic energy of any gas is the same, regardless the gas and other conditions.

This equation expresses it:

  • Avg KE = (3/2) (R / N) T

Where Avg KE is the average kinetic energy, R is the universal constant of gases, N is Avogadro's constnat, and T is the temperature measure in absolute scale (Kelvin).

As you see, in that equation Avg KE is propotional to T, which means that as the temperature is increased, the average kinetic energy increases.

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Formula of <br> Al³⁺ and SO₄²⁻
Sergio039 [100]

Answer:

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3 0
3 years ago
If you are given an ideal gas with pressure (P) = 259,392.00 Pa and temperature (T) = 2.00 oC
Anna [14]

Answer:

R=0·083 J/mol·K

Explanation:

Ideal gas equation is

<h3>P×V = n×R×T</h3>

where,

P is the pressure of the gas

V is the volume of the gas

n is the number of moles of the gas

R is ideal gas constant

T is the temperature of the gas in Kelvin

In case of given problem

Temperature of the gas = 273+2·00=275·00K

P=259,392·00×10^{-5} atm

(259,392·00×10^{-5} )×8·8 = 1×R×275·00

∴R=0·0830 J/mol·K

But according to the rules of significant figures the value of R must be with least precision of all the values of the other parameters from which the value of R is calculated

Here the least precision is in the volume as it contains only 2 significant digits

∴ Value of R must contain 2 significant digits

∴ R=0·083 J/mol·K

3 0
3 years ago
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