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Maksim231197 [3]
3 years ago
6

How many moles of hydrogen gas are produced when 3.8 moles of HCI are reacted? O 1.9 mol

Chemistry
1 answer:
igor_vitrenko [27]3 years ago
3 0
1.9 mol H2.
3.8 mol HCl * (1 mol H2 / 2 mol HCl) = 1.9 mol H2
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2 years ago
Which statement best describes comparative and descriptive investigations?
scZoUnD [109]

Answer:

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As the sun heats the surface of the oceans, two layers of water result. What separates the layers?
Basile [38]

Answer:

Thermocline separate these two layers.

Explanation:

Ocean consist of three major layers on the basis of temperature.

1. Upper layer

2. Deep layer

3. Thermocline

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Deep layer

The deep layer is present below the thermocline. It is present in deep where sunlight can not approach to it and its temperature remain low.

Thermocline

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4 0
3 years ago
A 0.4272 g sample of an element contains 2.241 x 10 ^21 atoms . what is the symbol of the element?
grin007 [14]

Answer:

Likely \rm In (indium.)

Explanation:

Number of atoms: N = 2.241 \times 10^{21}.

Dividing, N, the number of atoms by the Avogadro constant, N_A \approx 6.023 \times 10^{23} \; \rm mol^{-1}, would give the number of moles of atoms in this sample:

\begin{aligned} n &= \frac{N}{N_{A}} \\ &\approx \frac{2.241 \times 10^{21}}{6.023 \times 10^{23}\; \rm mol^{-1}} \approx 3.72 \times 10^{-3}\; \rm mol \end{aligned}.

The mass of that many atom is m = 0.4272\; \rm g. Estimate the average mass of one mole of atoms in this sample:

\begin{aligned}M &= \frac{m}{n} \\ &\approx \frac{0.4272\; \rm g}{3.72 \times 10^{-3}\; \rm mol} \approx 114.82\; \rm g \cdot mol^{-1}\end{aligned}.

The average mass of one mole of atoms of an element (114.82\; \rm g \cdot mol^{-1} in this example) is numerically equal to the average atomic mass of that element. Refer to a modern periodic table and look for the element with average atomic mass 114.82. Indium, \rm In, is the closest match.

5 0
3 years ago
Plz help ugh!! will upvote
erma4kov [3.2K]
All are CORRECT except (d)
6 0
3 years ago
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