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xenn [34]
3 years ago
7

Dos automóviles que marchan en el mismo sentido, se encuentran a una distancia de 126 Km. Si el más lento va a 42 Km/h, calcular

la velocidad del más rápido, sabiendo que le alcanza en seis horas.
Physics
1 answer:
puteri [66]3 years ago
5 0

Answer:

<em>La velocidad del más rápido deberá ser de 63 Km/h</em>

Explanation:

<u>Movimiento Rectilíneo Uniforme (MRU)</u>

Un cuerpo se dice que tiene MRU cuando recorre iguales distancias en tiempos iguales y en línea recta.

Tenemos dos automóviles viajando en el mismo sentido. Uno, el más lento va por delante del otro que le ancanzará en t=6 horas una vez que supere la ventaja que le lleva el otro.

La velocidad se puede calcular con la fórmula:

\displaystyle v=\frac{x}{t}

Donde x es la distancia y t el tiempo que tarda en recorrerla.

El vehículo más rápido alcanzará al otro cuando logre superar los x=126 Km que le lleva. Si esto lo hace en t=6 horas, entonces la velocidad adicional que deberá desarrollar es:

\displaystyle v=\frac{126}{6}=21\ Km/h

Esa velocidad se suma a la del primer vehículo y tendremos la velocidad necesaria: 42 Km/h + 21 Km/h = 63 Km/h

La velocidad del más rápido deberá ser de 63 Km/h

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