This question involves the concepts of tension, weight, and centripetal force.
The maximum speed, the mass can have before the string breaks is "10.26 m/s".
First, we will find the maximum tension force:
Tension = Weight
T = W = mg = (32.4 kg)(9.81 m/s²)
T = 317.84 N
Now, this tension force must be equal to the centripetal force:
where,
v = maximum speed = ?
r = radius = 1.21 m
m = mass = 3.65 kg
Therefore,
<u>v = 10.26 m/s</u>
Learn more about centripetal force here:
brainly.com/question/11324711?referrer=searchResults
The attached picture shows the centripetal force.
1) Acceleration of the sled
The acceleration of the sled is given by the net force acting in the direction parallel to the incline. There are two forces acting along this direction: the component of the weight parallel to the ramp (downward) and the friction (upward). Therefore, the net force acting in this direction is
And the acceleration is given by Newton's second law:
2) Normal force
The normal force acting on the sled is equal to the component of the weight perpendicular to the incline, therefore:
Answer: 1175 J
Explanation:
Hooke's Law states that "the strain in a solid is proportional to the applied stress within the elastic limit of that solid."
Given
Spring constant, k = 102 N/m
Extension of the hose, x = 4.8 m
from the question, x(f) = 0 and x(i) = maximum elongation = 4.8 m
Work done =
W = 1/2 k [x(i)² - x(f)²]
Since x(f) = 0, then
W = 1/2 k x(i)²
W = 1/2 * 102 * 4.8²
W = 1/2 * 102 * 23.04
W = 1/2 * 2350.08
W = 1175.04
W = 1175 J
Therefore, the hose does a work of exactly 1175 J on the balloon
Answer:
0.012 J
Explanation:
We are given:
q = 0.0080C
Potential difference = 1.5V
W=qV
Substituting the values into the equation:
W=0.0080*1.5= 0.012J
I need Explanation please
