1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
xenn [34]
3 years ago
7

Dos automóviles que marchan en el mismo sentido, se encuentran a una distancia de 126 Km. Si el más lento va a 42 Km/h, calcular

la velocidad del más rápido, sabiendo que le alcanza en seis horas.
Physics
1 answer:
puteri [66]3 years ago
5 0

Answer:

<em>La velocidad del más rápido deberá ser de 63 Km/h</em>

Explanation:

<u>Movimiento Rectilíneo Uniforme (MRU)</u>

Un cuerpo se dice que tiene MRU cuando recorre iguales distancias en tiempos iguales y en línea recta.

Tenemos dos automóviles viajando en el mismo sentido. Uno, el más lento va por delante del otro que le ancanzará en t=6 horas una vez que supere la ventaja que le lleva el otro.

La velocidad se puede calcular con la fórmula:

\displaystyle v=\frac{x}{t}

Donde x es la distancia y t el tiempo que tarda en recorrerla.

El vehículo más rápido alcanzará al otro cuando logre superar los x=126 Km que le lleva. Si esto lo hace en t=6 horas, entonces la velocidad adicional que deberá desarrollar es:

\displaystyle v=\frac{126}{6}=21\ Km/h

Esa velocidad se suma a la del primer vehículo y tendremos la velocidad necesaria: 42 Km/h + 21 Km/h = 63 Km/h

La velocidad del más rápido deberá ser de 63 Km/h

You might be interested in
How many Sig Figs (Significant Figures) are in each number?<br><br> 5070.0<br><br> 870.064080
nlexa [21]

∑ Hey, Lethality ⊃

Answer:

5070.0 has 5 significant figures

870.064080 has 9 significant figures

Explanation:

<u><em>Given:</em></u>

<em>How many Sig Figs (Significant Figures) are in each number?</em>

<em>5070.0</em>

<em>870.064080</em>

<u><em>Solution:</em></u>

<em>-------------------------------------------------------------------------------------------------------------</em>

<em>5070.0</em>

<em>5070.0 has 5 significant figures ( 5 , 0 , 7 , 0 , and 0 )</em>

<em>Number of significant figures: 5</em>

<em>-------------------------------------------------------------------------------------------------------------</em>

<em>870.064080</em>

<em>870.064080 has 9 significant figures ( 8, 7 ,0,0, 6,4,0,8 and 0 )</em>

<em>Number of significant figures: 9</em>

<em>-------------------------------------------------------------------------------------------------------------</em>

<em />

<u><em>xcookiex12</em></u>

<em>8/23/2022</em>

5 0
1 year ago
A force causes a mass of 4 kg to have an acceleration of 8 m/s2. Suppose something causes the mass to be one-quarter of its orig
solniwko [45]

Explanation:

From Newton's second law:

F = ma

Given that m = 4 kg and a = 8 m/s²:

F = (4 kg) (8 m/s²)

F = 32 N

If m is reduced to 1 kg and F stays at 32 N:

32 N = (1 kg) a

a = 32 m/s²

So the acceleration increases by a factor of 4.

5 0
3 years ago
The process of changing the energy of a system by means of force. Force * Diatance
Dmitry_Shevchenko [17]
This is known as work
7 0
3 years ago
What is the force on a box that is being pushed to the right with 50n of force while, at the same time, being pushed to the left
elena-s [515]
I think the question meant to say net force on the box. Since force is a vector, the direction matters. 20N left is negated completely by the 50N right, which means the net force is 50N-20N to the right, 30N. 
7 0
3 years ago
If the sprinter from the previous problem accelerates at that rate for 20 m, and then maintains that velocity for the remainder
kakasveta [241]

Question:

A 63.0 kg sprinter starts a race with an acceleration of 4.20m/s square. What is the net external force on him? If the sprinter from the previous problem accelerates at that rate for 20m, and then maintains that velocity for the remainder for the 100-m dash, what will be his time for the race?

Answer:

Time for the race will be t = 9.26 s

Explanation:

Given data:

As the sprinter starts the race so initial velocity = v₁ = 0

Distance = s₁ = 20 m

Acceleration = a = 4.20 ms⁻²

Distance = s₂ = 100 m

We first need to find the final velocity (v₂) of sprinter at the end of the first 20 meters.

Using 3rd equation of motion

(v₂)² - (v₁)² = 2as₁ = 2(4.2)(20)

v₂ = 12.96 ms⁻¹

Time for 20 m distance = t₁ = (v₂ - v ₁)/a

t₁ = 12.96/4.2 = 3.09 s

He ran the rest of the race at this velocity (12.96 m/s). Since has had already covered 20 meters, he has to cover 80 meters more to complete the 100 meter dash. So the time required to cover the 80 meters will be

Time for 100 m distance = t₂ = s₂/v₂

t₂ = 80/12.96 = 6.17 s

Total time = T = t₁ + t₂ = 3.09 + 6.17 = 9.26 s

T = 9.26 s

5 0
3 years ago
Other questions:
  • What is the weight of a 48 kg girl on Earth? Round the answer to the nearest whole number.
    6·2 answers
  • How is work defined in physics
    12·1 answer
  • Three cars (car F, car G, and car H) are moving with the same speed and slam on their brakes. The most massive car is car F, and
    9·1 answer
  • A 1.4-kg cart is attached to a horizontal spring for which the spring constant is 50 N/m . The system is set in motion when the
    10·2 answers
  • If a bicyclist is traveling at 40.0 km/hr for 2.5 hrs. How far does he travel?
    10·2 answers
  • When discussing Newton's laws of motion,which terms do people most likely yse when talking about Newton's third law of motion?​
    8·1 answer
  • Why the walls of tyres becomes warm as the car moves​
    13·1 answer
  • Please help!! This is the last question and i’m unsure! I will mark brainliest! Please try to provide a explanation you don’t ha
    13·1 answer
  • yghjgmbnjhmbhjhjbyghjgmbnjhmbhjhjbyghjgmbnjhmbhjhjbyghjgmbnjhmbhjhjbyghjgmbnjhmbhjhjbyghjgmbnjhmbhjhjbyghjgmbnjhmbhjhjbyghjgmbnj
    13·2 answers
  • Choose one inner planet and one outer planet and compare their similarities and differences.
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!