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Bas_tet [7]
1 year ago
11

How many Sig Figs (Significant Figures) are in each number? 5070.0 870.064080

Physics
1 answer:
nlexa [21]1 year ago
5 0

∑ Hey, Lethality ⊃

Answer:

5070.0 has 5 significant figures

870.064080 has 9 significant figures

Explanation:

<u><em>Given:</em></u>

<em>How many Sig Figs (Significant Figures) are in each number?</em>

<em>5070.0</em>

<em>870.064080</em>

<u><em>Solution:</em></u>

<em>-------------------------------------------------------------------------------------------------------------</em>

<em>5070.0</em>

<em>5070.0 has 5 significant figures ( 5 , 0 , 7 , 0 , and 0 )</em>

<em>Number of significant figures: 5</em>

<em>-------------------------------------------------------------------------------------------------------------</em>

<em>870.064080</em>

<em>870.064080 has 9 significant figures ( 8, 7 ,0,0, 6,4,0,8 and 0 )</em>

<em>Number of significant figures: 9</em>

<em>-------------------------------------------------------------------------------------------------------------</em>

<em />

<u><em>xcookiex12</em></u>

<em>8/23/2022</em>

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2 years ago
A mixture that appears to contain only one substance is a(n)
BartSMP [9]
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6 0
3 years ago
What are the first three overtones of a bassoon that has a fundamental frequency of 90.0 Hz? It is open at both ends. (The overt
vekshin1

Answer:

f_{2}=180Hz,f_{3}=270Hz,f_{4}=360Hz\\

Explanation:

Given data

Frequency f=90 Hz

To find

First three overtones of bassoon

Solution

The fundamental frequency of bassoon is found by substituting n=1 in below equation

f=v/λ=nv/2L

f_{1}=v/2L

The first overtone of bassoon is found by substituting n=2

So

f_{2}=2v/2L\\f_{2}=2(v/2L)\\as \\f_{1}=v/2L\\So\\f_{2}=2f_{1}\\f_{2}=2(90Hz)\\f_{2}=180Hz

The second overtone of bassoon is found by substituting n=3

So

f_{3}=3v/2L\\f_{3}=3(v/2L)\\as \\f_{1}=v/2L\\So\\f_{3}=3f_{1}\\f_{3}=3(90Hz)\\f_{3}=270Hz

The third overtone of bassoon is found by substituting n=4

So

f_{4}=4v/2L\\f_{4}=4(v/2L)\\as \\f_{1}=v/2L\\So\\f_{4}=4f_{1}\\f_{4}=4(90Hz)\\f_{4}=360Hz

5 0
3 years ago
A 40 lb box is suspended from two ropes which each make an angle of 45 degrees with the vertical. What is the tension (in pounds
givi [52]

Answer:

The tension on each rope is 28.28 lb

Explanation:

Given that,

Weight = 40 lb

Angle = 45°

We need to calculate the tension on each rope

Considering the symmetry of the system, the tension of each rope must be same

So,

T\sin\theta+T\sin\theta=mg

Put the value into the formula

2T\sin\theta=mg

T\times\sin45=\dfrac{40}{2}

T=\dfrac{40\sqrt{2}}{2}

T=28.28\ lb

Hence, The tension on each rope is 28.28 lb.

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2 years ago
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natita [175]

Answer:

I believe you are correct but we just started this unit

Explanation:

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