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3 years ago

13

Please help!! This is the last question and i’m unsure! I will mark brainliest! Please try to provide a explanation you don’t ha

ve to but atleast a short one

1 answer:

Flauer [41]3 years ago

7 0

Answer:

True

Explanation:

As of Newton's law, yes. Because when I land my feet on the ground, I apply a force. As per Newton's third law, the ground must apply the same force on me.

If its correct, may I hv brainliest?

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A ball starts from rest and accelerates at a constant rate of 1.0m/s to a final velocity of

den301095 [7]

Answer:

Time taken to reach final velocity = 5.5 second

Explanation:

Given:

Initial velocity (Starting from rest)(u) = 0 m/s

Acceleration of ball (a) = 1 m/s²

Final velocity (v) = 5.5 m/s

Find:

Time taken to reach final velocity

Computation:

Using first equation of motion;

v = u + at

where,

v = final velocity

u = initial velocity

a = acceleration

t = time taken

5.5 = 0 + (1)(t)

5.5 = t

Time taken to reach final velocity = 5.5 second

8 0

3 years ago

Question 1 of 15

Alex17521 [72]

You will always use your mind and logic in science not very sure what your question is asking but I think your ANSWER could most possibly be TRUE

4 0

3 years ago

When you see a straw in a glass of water it looks bent why is this ?

yuradex [85]

Because light is being refracted

6 0

3 years ago

Read 2 more answers

A neutron is confined in a one-demensional potential box of width 5.0 x 10^-15 m. Calculate the minimum kinetic energy of the ne

kvv77 [185]

Answer:

$E_1=1.31\times 10^{-12}\ J$

Explanation:

Given that,

Width of a one dimensional potential box, $x=5\times 10^{-15}\ m$

The energy of a particle in one dimensional box is given by :

$E_n=\dfrac{n^2h^2}{8mx^2}$

h = Planck's constant

m = the mass of the proton

For minimum kinetic energy, n = 1

$E_1=\dfrac{(6.63\times 10^{-34})^2}{8\times 1.67\times 10^{-27}\times (5\times 10^{-15})^2}$

$E_1=1.31\times 10^{-12}\ J$

So, the minimum kinetic energy of the neutron is $1.31\times 10^{-12}\ J$ . Hence, this is the required solution.

8 0

3 years ago

An aluminum wire with a diameter of 0.115 mm has a uniform electric field of 0.235 V/m imposed along its entire length. The temp

tekilochka [14]

Answer with Explanation:

We are given that

Diameter of coil=d=0.115mm

Radius, r= $\frac{d}{2}=\frac{0.115}{2}=0.0575mm=0.0575\times 10^{-3} m$

Using $1mm=10^{-3} m$

Electric field=E=0.235V/m

T=55 degree C

$T_0=20^{\circ} C$

$\rho_0=2.82\times 10^{-8}\Omega m$

$\alpha=3.9\times 10^{-3}/C$

(a).We know that

$\rho=\rho_0(1+\alpha(T-T_0))$

Substitute the values

$\rho=2.82\times 10^{-8}(1+3.9\times 10^{-3}(55-20))$

$\rho=3.2\times 10^{-8}\Omega m$

(b).Current density, $J=\frac{E}{\rho}$

Using the formula

$J=\frac{0.235}{3.2\times 10^{-8}}=7.3\times 10^6A/m^2$

c.Total current,I=JA

Where $A=\pi r^2$

$\pi=3.14$

Using the formula

$I=7.3\times 10^6\times 3.14\times (0.0575\times 10^{-3})^2$

I=0.076A

d.Length of wire=l=2m

$V=El$

Substitute the values

$V=0.235\times 2=0.47 V$

5 0

3 years ago