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anzhelika [568]
2 years ago
8

Find the AREA of the square below.: 2x + 3

Mathematics
1 answer:
Harrizon [31]2 years ago
5 0

5

the awsne ris some dunmber i dont know are ocare baout lol

5*3=8-e# jf

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Please help thank you!
Akimi4 [234]
C. is the answer

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3 0
2 years ago
∠A and ∠B are vertical angles. If m ∠A=(2x+26)∘ and ∠B=(3x−29)∘, then find the measure of ∠A.
Leya [2.2K]

The measure of angle (m ∠A) is 136°

<h3>Vertical angles theorem</h3>

From the question, we are to find the measure of angle A

From the given information, we have that

∠A and ∠B are vertical angles

Thus

∠A = ∠B

and

Also, from the given information,

m ∠A=(2x+26)°

and

m ∠B= (3x−29)°

∴ (2x+26)° = (3x−29)°

Now, solve for x

2x + 26 = 3x - 29

26 + 29 = 3x - 2x

55 = x

∴ x = 55

But measure of angle A is given by

m ∠A=(2x+26)°

Put the value of x into the equation,

m ∠A=(2(55)+26)°

m ∠A=(110+26)°

m ∠A = 136°

Hence, the measure of angle (m ∠A) is 136°

Learn more on Vertical angle theorem here: brainly.com/question/24839702

#SPJ1

6 0
1 year ago
6. Find the function with x-intercepts (-3,0) and (5,0), which also goes through the point (1,8)
Yakvenalex [24]

Answer:

f(x) = (-1/2)(x^2 + 8x - 15)

Step-by-step explanation:

This function has two roots:  -3 and 5.  Most likely it is a quadratic (all of which have two roots).

Then f(x) = a(x + 3)(x - 5)

The graph goes through (1. 8):  Therefore, y = 8 when x = 1:

f(1) = a(1 + 3)(1 - 5) = 8, or

        a(4)(-4) = 8, or

            -16a = 8, which leads to a = -1/2.

Thus the quadratic in question is f(x) = (-1/2)(x + 3)(x - 5), or

                                                        f(x) = (-1/2)(x^2 + 8x - 15)

4 0
2 years ago
The quotient of z and 4 please help me.
MAXImum [283]
"The quotient of z and 4"
is the same as saying
"z divided by 4"

z/4
3 0
3 years ago
Classify the triangle by its angles and sides
postnew [5]
Answer; A: Right scalene. Square on the corner tells you it's a right triangle. It's a scalene triangle because none of the sides are equal.
7 0
1 year ago
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