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4 years ago

15

Which number should come next in the series? 1 - 1 - 2 - 3 - 5 - 8 - 13

1 answer:

Darya [45]4 years ago

8 0

This is part of the Fibonacci sequence. The next number is 21. Look at how much each number increases and the number before it.

1+1=2 (the number after 1 and 1)
1+2=3 (the number after 1 and 2)
2+3=5 (the number after 2 and 3)

So to solve we add 13+8=21

You might be interested in

Change the subject of the formula L = v 4kt - p to k.

Romashka [77]

Answer:

$\boxed{k = \frac{L^2 + p}{4t}}$

General Formulas and Concepts:

<u>Algebra I</u>

Basic Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify given.</em>

<em /> $\displaystyle L = \sqrt{4kt - p}$

<u>Step 2: Solve for </u><u><em>k</em></u>
We can use equality properties to help us rewrite the equation to get <em>k</em> as our subject:

Let's first <em>square both sides</em>:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\\end{aligned}$

Next, <em>add p to both sides</em>:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\\end{aligned}$

Next, <em>divide 4t by both sides</em>:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow L^2 = \big( \sqrt{4kt - p} \big) ^2 \\& \rightarrow L^2 = 4kt - p \\& \rightarrow L^2 + p = 4kt \\& \rightarrow \frac{L^2 + p}{4t} = k \\\end{aligned}$

We can rewrite the new equation by swapping sides to obtain our final expression:

$\displaystyle\begin{aligned}L = \sqrt{4kt - p} & \rightarrow \boxed{k = \frac{L^2 + p}{4t}}\end{aligned}$

∴ we have <em>changed</em> the subject of the formula.

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Learn more about Algebra I: brainly.com/question/27698547

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Topic: Algebra I

6 0

2 years ago

An element with mass 330 grams decays by 25. 5% per minute. How much of the element is remaining after 5 minutes, to the nearest

yaroslaw [1]

The amount of mass after 5 minutes is 75.74 grams.

It is given that

The amount initially = 330grams

After every minute mass decays by 25.5%

<h3>What is the percentage?</h3>

The percentage is the value per hundred.

Amount after 1 min = 330-330*25.5/100 = 245.85grams

Amount after 2 min = 245.85-245.85*25.5/100 = 183.16grams

Amount after 3min = 183.16-183.16*25.5/100 = 136.45grams

Amount after 4 min = 136.45-136.45*25.5/100= 101.66grams

Amount after 5 min =101.66-101.66*25.5/100 = 75.74grams

Therefore, the amount of mass after 5 minutes is 75.74 grams.

To get more about percentage visit:

brainly.com/question/24304697

7 0

2 years ago

Elena and Matthew are president and vice-president of their ninth-grade class at Riverside High School. They have suggested that

dimulka [17.4K]

250 + 100 = 350

350 + 1000 = 1350

1350 / 5 = 270

they need to sell 270 tickets

answer is B

4 0

3 years ago

Read 2 more answers

Forty tickets are sold for a raffle with two prizes. You buy two tickets. What is the probability that you will win both prizes?

Trava [24]

Well, the first one is 2/40=1/20. The 2nd one is 1/39. You multiply these to get 1/780.

5 0

3 years ago

Isabella worked 50 hours over the past two weeks, and she gets paid by the hour. During the first week of the two-week span, she

mestny [16]

$475. because 285/30 = 9.5 and 9.5 x 50 = 475

6 0

3 years ago

Read 2 more answers