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Vikentia [17]
3 years ago
8

Need help on this question asap please

Mathematics
1 answer:
marysya [2.9K]3 years ago
4 0

Answer:

G = (y-x)/2

Step-by-step explanation:

Here, we want to find the value of the angle marked G

To do this, we are going to use one of the important circle angle-arc relationships

Thus, we have it that;

G = 1/2 (mFE - mJH)

G = 1/2 (y-x)

Which is simply

G = (y-x)/2

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Write the equation of the line perpendicular to + = that passes through (−,−). Write your answer in slope-intercept form.
Ad libitum [116K]

Answer:

y = 0.25x - 5

Step-by-step explanation:

Given line is 4x + y = 3

or y = -4x + 3

Comparing this with slope-intercept form y = mx + c :

slope of this line is -4

Product of slopes of perpendicular lines = -1

⇒ slope of a line perpendicular to this is \frac{-1}{-4} = \frac{1}{4} = 0.25

This line also passes through the point (-4,-6)

The equation of a line having slope m and passing through a point (h,k) is

y - k = m(x - h)

⇒ equation of line perpendicular to given line is y - (-6) = 0.25×{x - (-4)}

⇒ y + 6 = 0.25×(x + 4)

⇒ y + 6 = 0.25x + 1

⇒ <u>y = 0.25x - 5</u>

This is in the slope-intercept form y = mx + c with slope m = 0.25 and y-intercept (0,-5)

6 0
3 years ago
The sides of a rectangle are enlarged by a scale factor of 2. Write
Dennis_Churaev [7]

Answer:

4

Step-by-step explanation:

both sides are multiplied by 2 which means its the original area*2*2 which means it's the original area*4

5 0
2 years ago
Solve the equation x-20.7=9.5 for x
kenny6666 [7]
The answer will come out to 30.2
8 0
2 years ago
Read 2 more answers
Find the equation of the line that passes through the point of intersection of x + 2y = 9 and 4x -2y = -4 and the point of inter
Rudik [331]

Answer:

y=-6x+10

Step-by-step explanation:

The point of intersection of

x+2y=9...eqn1


and


4x-2y=-4...eqn2

is the solution of the two equations.


We add equation (1) and equation(2) to get,

x+4x+2y-2y=9+-4


\Rightarrow 5x=5


\Rightarrow x=1

We put x=1 into equation (1) to get,

1+2y=9

\Rightarrow 2y=9-1

\Rightarrow 2y=8

\Rightarrow y=4


Therefore the line passes through the point, (1,4).


The line also passes through the point of intersection of

3x-4y=14...eqn(3)

and

3x+7y=-8...eqn(4)

We subtract equation (3) from equation (4) to obtain,

3x-3x+7y--4y=-8-14


\Rightarrow 11y=-22

\Rightarrow y=-2


We substitute this value into equation (4) to get,

3x+7(-2)=-8


3x-14=-8


3x=-8+14


3x=6

x=2

The line also passes through

(2,-2)



The slope of the line is

slope=\frac{4--2}{1-2} =\frac{6}{-1}=-6


The equation of the line is

y+2=-6(x-2)

y+2=-6x+12


y=-6x+10 is the required equation





4 0
3 years ago
Right Triangle Trigonometry:Question 10
alex41 [277]

Answer:

the qns is too big can you shortened

7 0
3 years ago
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