Answer:
A(t) = 300 -260e^(-t/50)
Step-by-step explanation:
The rate of change of A(t) is ...
A'(t) = 6 -6/300·A(t)
Rewriting, we have ...
A'(t) +(1/50)A(t) = 6
This has solution ...
A(t) = p + qe^-(t/50)
We need to find the values of p and q. Using the differential equation, we ahve ...
A'(t) = -q/50e^-(t/50) = 6 - (p +qe^-(t/50))/50
0 = 6 -p/50
p = 300
From the initial condition, ...
A(0) = 300 +q = 40
q = -260
So, the complete solution is ...
A(t) = 300 -260e^(-t/50)
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The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.
Answer:
y = -2x - 3
Step-by-step explanation:
-solve for y: y = 1/2x + 2
-perpendicular equals opposite slope: -2
-plug in the point: (1) = -2(-2) + b
1 = 4 + b
b = -3
put it all together: y = -2x - 3
Answer:
Increases, increase
Step-by-step explanation:
Density is M×V, meaning if one goes up and one stays the same, it goes up.
Answer:
the correct structure would be B
That would be the first choice:
5^0 = 1 , 5^1 = 5, 5^2 = 25 and so on up to 5^4 = 625
