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ikadub [295]
2 years ago
7

Riders are associated with what divice

Chemistry
1 answer:
deff fn [24]2 years ago
5 0
D you welcome lovey.
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How many liters of a 2.0 M solution of HCl do you need to have 8.0 moles of HCI?
kakasveta [241]

Answer:

1M HCl: add 1mol/12M = 83 ml conc. HCl to 1L of water or 8.3ml to 100ml.

2M HCl: add 2mol/12M = 167 ml conc. HCl to 1L of water or 16.7ml to 100ml.

4 0
2 years ago
25 mL of 0.10 M aqueous acetic acid is titrated with 0.10 M NaOH(aq). What is the pH after 30 mL of NaOH have been added?
weeeeeb [17]

Answer:

pH = 11.95≈12

Explanation:

Remember  the reaction among aqueous acetic acid (CH_3COOH) and aqueous sodium hydroxide (NaOH)

CH_3COOH + NaOH ->  CH_3COONa + H_2O

First step. Need to know how much moles of the substances are present

0.1 \frac{mol NaOH}{L} * 0.030 L = 0.003 mol NaOH[tex]0.1 \frac{mol CH_3COOH}{L} * 0.025 L= 0.0025 mol CH_3COOHSecond step. Know wich substance is in excess.0.0025 mol CH_3COOH * [tex]1 mol NaOH/ 1 mol CH_3COOH = 0.0025 mol NaOH

0.003 mol NaOH * 1 mol CH_3COOH/ 1 mol NaOH = 0.003 mol CH_3COOH[/tex]

NaOH is in excess. Now, how much?

0.003 mole NaOH - 0.0025 mole NaOH = 0.0005 mole NaOH

Then, that amount in excess would be responsable for the pH.

Third step. Know the pH

Remember that pH= -log[H+]

According to the dissociation of water equilibrium

Kw=[H+]*[OH-]= 10^(-14)

The dissociation of NaOH is

NaOH -> Na^{+} + OH^{-}

Now, concentration of OH^{-}[/tex] would be given for the excess of NaOH.

[OH-]= 0.0005 mole / 0.055 L = 0.00909 M

Careful: we have to use the total volumen

Les us to calculate pH

pH= -log [H+]\\pH= -log \frac{K_w}{[OH-]} \\pH= 11.95

6 0
3 years ago
Use the following chemical equation to answer the question:
garik1379 [7]

2 atome nitrogen , 1 is correct

5 0
3 years ago
PLEASE HELP ME!!
ivann1987 [24]

Answer: K and Mg

Explanation:

The first one refers to the atomic radius and increases going down and to the left on the periodic table. K is in between Rb and Na.

6 0
3 years ago
Pulses A, B, C, and D all travel at 10 m/s on the same string but in opposite directions. The string is depicted at time t=0 in
Anit [1.1K]

(a) The displacement of point P at time t=0.10s is determined as +2cm.

(b) The displacement of point P at time t=0.20s is determined as -2cm.

<h3>What is displacement?</h3>

Displacement is the change in position of an object. It is obtained from the product of velocity and time of motion.

x = vt

<h3>Displacement of the waves after 0.1 s</h3>

x = 10 m/s x 0.1 s = 1 m

Each wave will travel 1 m to the right or to the left, depending on the initial direction.

  • wave B from left will stop at point 0 m
  • wave A from left will stop at point -1 m
  • wave C from right will stop at point 0 m
  • wave D from right will stop at point + 1 m

wave B and C superimposed and the displacement will be between A and D.

Amplitude of A = - 2cm

Amplitude of D = + 4cm

Displacement of point P = 4 cm - 2 cm =  2cm

<h3>Displacement of the waves after 0.2 s</h3>

x = 10 m/s x 0.1 s = 2 m

Each wave will travel 2 m to the right or to the left, depending on the initial direction.

  • wave B from left will stop at point 1 m
  • wave A from left will stop at point 0 m
  • wave C from right will stop at point -1 m
  • wave D from right will stop at point 0 m

Displacement of point P = (amplitude B + amplitude C) + (amplitude A + amplitude D)

Displacement of point P= (2cm - 2cm) + (2 cm - 4cm)= -2cm

Learn more about displacement here: brainly.com/question/2109763

#SPJ1

8 0
2 years ago
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