Question

What is the mass (in kg) of 2.16 • 10^24 atoms of lead?

Answer 1

Answer:

0.783 kg

Explanation:

You must make the conversions:

atoms of Pb ⟶ moles of Pb ⟶ grams of Pb ⟶ moles of Pb

$\text{Moles of Pb} = 2.16 \times 10^{24} \text{ atoms Pb} \times \frac{\text{1 mol Pb} }{ 6.022 \times 10^{23} \text{ atoms Pb} } = \text{3.589 mol Pb}$

$\text{Mass of S} = \text{3.589 mol Pb} \times \frac{\text{207.2 g Pb}}{\text{1 mol Pb} } = \text{743 g Pb = 0.783 kg Pb}$