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3 years ago

-58 3 - 3 1 - 0 Solve.

Mathematics

1 answer:

jarptica [38.1K]3 years ago

5 0

Answer:

$-9\frac{1}{4}$

Step-by-step explanation:

Rewrite our equation with parts separated

-5 - $\frac{3}{4}$ - 3 - $\frac{1}{2}$

Solve the whole number parts

-5 - 3 = -8

Solving the fraction parts and Find the LCD

LCD = 4

$-\frac{3}{4}$ - $\frac{2}{4}$ = $-\frac{5}{4}$

Simplify

$-\frac{5}{4} = -1\frac{1}{4}$

Combine the whole and fraction parts

8 - 1 - $\frac{1}{4}$ = $-9\frac{1}{4}$

Mark as Brainllest

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Answer:

a) $n=\frac{0.675(1-0.675)}{(\frac{0.02}{1.64})^2}=1475.07$

And rounded up we have that n=1476

b) $n=\frac{0.5(1-0.5)}{(\frac{0.02}{1.64})^2}=1681$

And rounded up we have that n=1681

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

If solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by $\alpha=1-0.9=0.1$ and $\alpha/2 =0.05$ . And the critical value would be given by: