Answer :
Heating takes place during the process of Evaporation, Melting, Sublimation.
Cooling takes place during the process of Freezing, Condensation, Deposition.
Explanation :
Heating : It means thermal energy releases.
Cooling : It means thermal energy absorbs.
Evaporation : It is a type of vaporization process in which a liquid changes into gas phase by providing heat.
Melting : It is a process in which a solid changes into liquid phase by providing heat.
Sublimation : It is a process in which a solid changes directly into gas phase without passing through a liquid phase.
Freezing : It is a process in which a liquid transform into a solid phase at low temperature.
Condensation : It is a process in which a water vapor(gas) changes into liquid state at low temperature.
Deposition : It is a process in which a gas transforms directly into a solid phase without passing through a liquid phase.
47% yield.
First, let's determine how many moles of ethane was used and how many moles of CO2 produced. Start with the respective atomic weights.
Atomic weight carbon = 12.0107
Atomic weight hydrogen = 1.00794
Atomic weight oxygen = 15.999
Molar mass C2H6 = 2 * 12.0107 + 6 * 1.00794 = 30.06904 g/mol
Molar mass CO2 = 12.0107 + 2 * 15.999 = 44.0087 g/mol
Moles C2H6 = 8 g / 30.06904 g/mol = 0.266054387 mol
Moles CO2 = 11 g / 44.0087 g/mol = 0.249950578 mol
Looking at the balanced equation, for every 2 moles of C2H6 consumed, 4 moles of CO2 should be produced. So at 100% yield, we should have 0.266054387 / 2 * 4 = 0.532108774 moles of CO2. But we only have 0.249950578 moles, or 0.249950578 / 0.532108774 = 0.46973587 =
46.973587% of what was expected.
Rounding to 2 significant figures gives 47% yield.
Answer: 1.79 x 10^-5
Explanation: The equilibrium constant of a reaction can be calculated from the quotient of the concentrations of the products over the concentrations of the reactants, with each termed raised to their respective stoichometric coefficients.
For acetic acid, this equilibrium expression is:
![Kc=\frac{[H+] [CH3COO-]}{[CH3COOH]}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BH%2B%5D%20%5BCH3COO-%5D%7D%7B%5BCH3COOH%5D%7D)
Replacing the equilibrium concentrations given by the exercise into the expression above, the equilibrium constant, Kc will be obtained and it is found to be equal to 1.79 x 10^-5.
First you would multiply 5,3, and 2 to get a volume of 30. Density is mass over volume so you would then divide 129 by 30. You would get 4.3. The answer would be 4.3 g/cm^3
