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babunello [35]
3 years ago
10

How is the chemical formula of a compound determined?

Chemistry
1 answer:
Andrej [43]3 years ago
6 0
I hope this help to you

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sergij07 [2.7K]
Not 100% sure but I think 40 seconds
4 0
3 years ago
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2. This graph shows the energy involved in a reaction involving two molecules. Describe what is happening or what the state of t
blagie [28]
If you think of it endothermic is when there is energy needed for the reaction to occur and exothermic is when the reaction releases energy
6 0
3 years ago
Help?
Ahat [919]

Answer:

KClO_3

Explanation:

Hello!

In this case, as we know the mass of the total sample, we can first compute the mass of oxygen:

m_O=22.9g-7.33g-6.65g=8.92g

Next, we compute the moles of each element:

n_K=\frac{7.33g}{39.9g/mol}= 0.184mol\\\\n_{Cl}=\frac{6.65g}{35.45g/mol}=0.188mol \\\\n_O=\frac{8.92g}{16.00g/mol} =0.5575mol

Now, we divide the moles by 0.184 moles, the fewest ones, to obtain:

K=\frac{0.184}{0.184}=1.0 \\\\Cl=\frac{0.187}{0.184}=1.0\\\\O=\frac{0.5575}{0.184}  =3.0

Therefore, the empirical formula is:

KClO_3

Regards!

3 0
2 years ago
At 400 K, the rate of decomposition of a gaseous compound initially at a pressure of 12.6 kPa, was 9.71 Pa s-1 when 10.0 per cen
Neporo4naja [7]

Answer:

The order of the reaction with respect to the gas = 2

Explanation:

Let the original gas pressure be [G₀]

Initial rate of reaction is given as

r = k [G₀]ⁿ

When 10% had reacted, amount of gas left = [0.9G₀], r = 9.71 Pa/s

r = k [0.9G₀]ⁿ = 9.71 (eqn 1)

when 20% had reacted, amount of gas left = [0.8G₀], r = 7.67 Pa/s

r = k [0.8G₀]ⁿ = 7.67 (eqn 2)

Dividing (eqn 1) by (eqn 2)

(9.71/7.67) = [0.9/0.8]ⁿ

1.266 = 1.125ⁿ

1.125ⁿ = 1.266

Take natural logarithms of both sides

n (In 1.125) = In 1.266

n = 0.236/0.118

n = 2.

7 0
3 years ago
At 25 °C with 10 g/kg of water vapor in the air, precipitation is likely or not likely.
Lapatulllka [165]

Answer:

Not likely

Explanation:

It would only be likely if the humidity was high enough to rain.

so, it is not likely

6 0
3 years ago
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