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Vsevolod [243]
3 years ago
5

In which quadrant is the number –14 – 5i located on the complex plane?

Mathematics
1 answer:
loris [4]3 years ago
5 0

Answer:

The complex number r = -14 - i\,5 belongs to the third quadrant of the complex plane.

Step-by-step explanation:

Let be r = -14 - i\,5. In the complex plane, if \Re (r) < 0 (real component) and \Im (r) < 0 (imaginary component), the number belongs to the third quadrant of the complex plane. The complex number r = -14 - i\,5 belongs to the third quadrant of the complex plane.

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See image attached below keeeeeeeeeeeeeeeeeeeed
emmasim [6.3K]

Answer:

.13%

68.26%

2.28%

47.72%

49.87%

34.13%

Step-by-step explanation:

1.) standardize by subtracting the mean and dividng by the standard deviation

(625-1000)/125= -3

go to a ztable to get .0013 or (1-.9987)

this is equal to .13%

2.)

875<x<1125

standardize both seperately and subtract them

(875-1000)/125= -1  whose probability is .1587 (or 1-.8413)

(1125-1000)/125= 1  whose probability is .8413

.8413-.1587= 68.26%

3.)

Find the probability that someone paid less than 1250 and take its compliment

(1250-1000)/125= 2 which has a probability of .9772

take its compliment (1-.9772)= .0228= 2.28%

4.)

Same process as question 2

(750-1000)/125= -2 which has a probability of (1-.9772) = .0228

(1000-1000)/125= 0 which has a probability of .5

.5-.0228= .4772= 47.72%

5.) same deal as the previous question

(625-1000)/125= -3 which has a probability of (1-.9987)= .0013

(1000-1000)/125= 0 which has a probability of .5

.5-.0013= .4987= 49.87%

6.)same deal the previous question

(875-1000)/125= -1 which has a probability of (1-.8413)=.1587

(1000-1000)/125= 0 which has a probability of .5

.5-.1587= .3413= 34.13%

4 0
3 years ago
8 less than a number n is less than 11
iragen [17]

In mathematical form, it would be:

n-8 < 11

add 8 from both sides,

n-8+8 < 11+8

n < 19

So, n value must be less than 19

Hope this helps!

8 0
4 years ago
Write an equation in slope-intercept form of the line that passes through the points (-2, - 11) and (3,9).
I am Lyosha [343]

Answer:

y = 4x - 3

Step-by-step explanation:

(-2, -11) & (3, 9)

First you want to find the slope of the line that passes through these points. To find the slope of the line, we use the slope formula: (y₂ - y₁) / (x₂ - x₁)

Plug in these values:

(9 - (-11)) / (3 - (-2))

Simplify the parentheses.

= (20) / (5)

Simplify the fraction.

20/5

= 4

This is your slope. Plug this value into the standard slope-intercept equation of y = mx + b.

y = 4x + b

To find b, we want to plug in a value that we know is on this line: in this case, I will use the second point (3, 9). Plug in the x and y values into the x and y of the standard equation.

9 = 4(3) + b

To find b, multiply the slope and the input of x(3)

9 = 12 + b

Now, subtract 12 from both sides to isolate b.

-3 = b

Plug this into your standard equation.

y = 4x - 3

This is your equation.

Check this by plugging in the other point you have not checked yet (-2, -11).

y = 4x - 3

-11 = 4(-2) -3

-11 = -8 - 3

-11 = -11

Your equation is correct.

Hope this helps!

8 0
3 years ago
Question 10 of 13
murzikaleks [220]
C is the correct answer
8 0
3 years ago
Read 2 more answers
***mathtest timed***
Gre4nikov [31]
The answer is option A
6 0
3 years ago
Read 2 more answers
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