Emergency!!!!!!
1 answer:
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the complete question in the attached figure
a) we know that
T - mg = mv^2/r
The net forces equal the mass times the centripetal acceleration
So
T=50 N
m=3 kg
r=0.60 m
v = sqrt((T-mg)r/m) = sqrt((50-(3*9.8))*(.60)/3) = 2.03 m/s
the answer part a) is 2.03 m/s
b) At the top the equation becomes T+mg=mv^2/r
but here the critical speed occurs when T = 0
so the critical speed is v = sqrt(rg) = sqrt (.60*9.80) = 2.42 m/s
the answer part b) is 2.42 m/s
a) we know that
T - mg = mv^2/r
The net forces equal the mass times the centripetal acceleration
So
T=50 N
m=3 kg
r=0.60 m
v = sqrt((T-mg)r/m) = sqrt((50-(3*9.8))*(.60)/3) = 2.03 m/s
the answer part a) is 2.03 m/s
b) At the top the equation becomes T+mg=mv^2/r
but here the critical speed occurs when T = 0
so the critical speed is v = sqrt(rg) = sqrt (.60*9.80) = 2.42 m/s
the answer part b) is 2.42 m/s