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Paladinen [302]

3 years ago

12

My cat weighs 80 N. The area of the bottom of her foot is approximately 0.0045 m(squared). if she stands on one foot and lost ha

lf it's weight, how much pressure is exerting on the cat's paw?

1 answer:

Sonja [21]3 years ago

4 0

Answer:

P = F / A = 40 N / (0.0045 m^2) = 8889 N/m^2

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