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fredd [130]
3 years ago
13

3. Charles and Jaden share a reward of $63 in a ratio of 2 : 5. How much does Jaden get?

Mathematics
1 answer:
marissa [1.9K]3 years ago
3 0

Answer:

Jaden received: $45

Step-by-step explanation:

$63 : 7 = 9 => $9 * 5 = $45

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The answer is in the attachment

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Solve for k. 8k 2m = 3m k
Paha777 [63]
<span>Simplifying 8k + 2m = 3m + k Reorder the terms: 8k + 2m = k + 3m Solving 8k + 2m = k + 3m Solving for variable 'k'. Move all terms containing k to the left, all other terms to the right. Add '-1k' to each side of the equation. 8k + -1k + 2m = k + -1k + 3m Combine like terms: 8k + -1k = 7k 7k + 2m = k + -1k + 3m Combine like terms: k + -1k = 0 7k + 2m = 0 + 3m 7k + 2m = 3m Add '-2m' to each side of the equation. 7k + 2m + -2m = 3m + -2m Combine like terms: 2m + -2m = 0 7k + 0 = 3m + -2m 7k = 3m + -2m Combine like terms: 3m + -2m = 1m 7k = 1m Divide each side by '7'. k = 0.1428571429m Simplifying k = 0.1428571429m</span>
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3 years ago
How do you solve this problem. I need help with this equation. Can you help me?
bixtya [17]
5x + 2y = 13
x + 2y = 9
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4x = 4
x = 1

x + 2y = 9
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answer (1,4)
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4 0
3 years ago
If cos x= 5/13 and sin x &lt;0 find cos (x/2) and sin (2x)
taurus [48]
We know that

if cos x is positive
and
sin x is negative
so
the angle x belong to the IV quadrant

cos x=5/13
we know that
sin²x+cos²x=1-------> sin²x=1-cos²x------> 1-(5/13)²---> 144/169
sin x=√(144/169)-------> sin x=12/13
but remember that x is on the IV quadrant
so
sin x=-12/13

Part A) <span>cos (x/2)
cos (x/2)=(+/-)</span>√[(1+cos x)/2]
cos (x/2)=(+/-)√[(1+5/13)/2]
cos (x/2)=(+/-)√[(18/13)/2]
cos (x/2)=(+/-)√[36/13]
cos (x/2)=(+/-)6/√13-------> cos (x/2)=(+/-)6√13/13
the angle (x/2) belong to the II quadrant
so
cos (x/2)=-6√√13/13

the answer Part A) is 
cos (x/2)=-6√√13/13

Part B) sin (2x)
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the answer Part B) is 
sin(2x)=-120/169
4 0
3 years ago
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