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3 years ago

Please help me ASAP!!!!!!!!!

Mathematics

2 answers:

MariettaO [177]3 years ago

8 0

Answer:

omg and I thought I was the only one up this late doing a assessment.

Step-by-step explanation:

lakkis [162]3 years ago

4 0

The answer is 7/8. the equation is y2-y1 over x2-x1

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How many ones equal 9 tens?

Scilla [17]

90 one's are equal to 9 tens

4 0

3 years ago

Dana reflects point A(2,5) across line small script letter lℓ to get image point Upper A primeA′(6,1). What is an equation for

valentinak56 [21]

Firstly, we will draw diagram of the scenario

Dana reflects point A(2,5) across line small script letter lℓ to get image point Upper A primeA′(6,1)

It means that AA' is perpendicular bisects of line(l)

so, let's assume it intersects at point M

so, M will be mid-point between A and A'

$M=(\frac{2+6}{2},\frac{5+1}{2})$

$M=(4,3)$

M is a point on line (l)

now, we will find slope of line on AA'

x1=2 , y1=5

x2=6 , y2=1

$m=\frac{y_2-y_1}{x_2-x_1}$

now, we can plug values

$m=\frac{1-5}{6-2}$

$m=-1$

now, we know that line (l) and AA' are perpendicular to each other

so, slope of line(l) is -1/m

slope=1

so, we have slope and a point

$m=1$

$M=(4,3)$

now, we can use point slope form of line

$y-y_1=m(x-x_1)$

now, we can plug values

$y-3=1(x-4)$

$y=x-1$

so, the equation of line (l) is

$y=x-7$ ..............Answer

7 0

3 years ago

Read 2 more answers

Mia has 9 books. One third of her books are fairy tales. How many of mia's books are fairy tales?

Yuri [45]

The answer is 3

Hope this helps!

8 0

3 years ago

Read 2 more answers

Please check my homework on Negative Indices!

rusak2 [61]

Our first expression is $(2p^{-3} q^{8} )^{4}$ . Upon distributing the exponent 4 on all the terms, we get:

$(2p^{-3} q^{8} )^{4}=2^{4}(p^{-3})^{4}(q^{8})^{4}=16p^{-12}q^{32}=\frac{16q^{32}}{p^{12}}$

Therefore, your answer is correct for this part. :)

Second expression is $(2m^{-4}n^{5})^{-2}$ . Upon distributing the exponent -2 on all the terms, we get:

$(2m^{-4}n^{5})^{-2}=2^{-2}(m^{-4})^{-2}(n^{5})^{-2}=2^{-2}m^{8}n^{-10}=\frac{m^{8}}{4n^{10}}$

Your second answer is correct too.

Our third expression is $2(5g^{-4}h^{-6})^{2}$ . Upon distributing the exponent 2 on all the terms, we get:

$2(5g^{-4}h^{-6})^{2}=2(5^{2})(g^{-4})^{2}(h^{-6})^{2}=2(25)g^{-8}h^{-12}=\frac{50}{g^{8}h^{12}}$

This one is not correct. Your answer would have been correct, if the exponent were -2 instead of 2 in this part.

Our forth and last expression is $4(2c^{-3}d^{6})^{-5}$ . Upon distributing the exponent -5 on all the terms inside the parenthesis, we get:

$4(2c^{-3}d^{6})^{-5}=4(2^{-5})(c^{-3})^{-5}(d^{6})^{-5}=\frac{4}{2^{5}}(c^{15})(d^{-30})=\frac{4c^{15}}{32d^{30}}=\frac{c^{15}}{8d^{30}}$

Therefore, your answer for this part is also correct.

Looking at your work, I don't think you made a mistake in number 3 also, probably mis-typed the question while writing here :)

3 0

4 years ago

I need help on my math

atroni [7]

So multiple the largest eastern city by the smallest eastern city so 305 - 90
Then do the same for the western cities so 503 - 47
Now subtract the results to find the difference in the range of eastern vs western cities

5 0

3 years ago

Read 2 more answers