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Illusion [34]
3 years ago
12

Erika is working on solving the exponential equation 50x = 17; however, she is not quite sure where to start. Using complete sen

tences, describe to Erika how to solve this equation.
Hint: Use the change of base formula: log base b of y equals log y over log b.

Mathematics
1 answer:
valina [46]3 years ago
8 0

Answer:

Step-by-step explanation:

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A firm has a debt to asset ratio of 75%, $264,000 in debt, and net income of $49,280. calculate return on equity
svlad2 [7]
Asset = 264,000 / 0.75 = $352,000
Shareholders equity = $352,000 - $264,000 = 88,000

Return on equity = 49,280 / 88,000 x 100% = 56%
3 0
3 years ago
Quick pleaseeeeeeeeeeeee!!!!
pentagon [3]

Answer:

plot points at (0,4),(3,1),(5,7),(8,5)

Step-by-step explanation:

hope this helps (:

7 0
3 years ago
Simplify each expression by combining like terms <br> 3x^-1 - 10x^-1
Dmitry_Shevchenko [17]

Answer:

-7/x

Step-by-step explanation:

first, you combine the terms together to get -7x^-1. you cant have negative exponents in the numerator so you move the x^-1 to the denominator. once it move its becomes positive then.

7 0
3 years ago
The value of a certain car decreases by 16% each year. What is the 1⁄2-life of the car?
svet-max [94.6K]

Answer:

The half life of the car is 3.98 years.

Step-by-step explanation:

The value of the car after t years is given by the following equation:

V(t) = V(0)(1-r)^{t}

In which V(0) is the initial value and r is the constant decay rate, as a decimal.

The value of a certain car decreases by 16% each year.

This means that r = 0.16

So

V(t) = V(0)(1-r)^{t}

V(t) = V(0)(1-0.16)^{t}

V(t) = V(0)(0.84)^{t}

What is the 1⁄2-life of the car?

This is t for which V(t) = 0.5V(0). So

V(t) = V(0)(0.84)^{t}

0.5V(0) = V(0)(0.84)^{t}

(0.84)^{t} = 0.5

\log{(0.84)^{t}} = \log{0.5}

t\log{0.84} = \log{0.5}

t = \frac{\log{0.5}}{\log{0.84}}

t = 3.98

The half life of the car is 3.98 years.

7 0
3 years ago
solo el 20% de los empleados de la población civil que está en una base militar restringida porta su identificación personal. Si
prisoha [69]

Usando la distribución binomial, hay una probabilidad de 0.8926 = 89.26% de que el guardia de seguridad encuentre al menos uno en la base militar restringida.

<h3>¿Qué es la distribución binomial?</h3>

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

Los parámetros son:

  • n es el número de ensayos.
  • p es la probabilidad de éxito en un ensayo
  • x es el número de éxitos

En este problema, hay que:

  • 20% de los empleados de la población civil que está en una base militar restringida porta su identificación personal, o sea p = 0.2.
  • Llegan 10 empleados, o sea, n = 10.

La probabilidad de que el guardia de seguridad encuentre al menos uno en la base militar restringida es dada por:

P(X \geq 1) = 1 - P(X = 0)

En que:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.2)^{0}.(0.8)^{10} = 0.1074

Por eso:

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.1074 = 0.8926

Hay una probabilidad de 0.8926 = 89.26% de que el guardia de seguridad encuentre al menos uno en la base militar restringida.

Puede-se aprender más a cerca de la distribución binomial en brainly.com/question/25132113

3 0
2 years ago
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