9³
Step-by-step explanation:
nine to the third power or 9-cubed is the answer b/c multiply the number "9" by itself, three times.
Therefore, 9*9*9" is equal to: 9³
21) 3(2j-k)=108 It is asking you to set the equation equal to j
distribute the 3
6j-3k=108
move k to the other side by adding on both sides
6j=108+3k
divide everything by 6
j=18+0.5k
Answer:
b=-2aH
Step-by-step explanation:
H=-b/2a
Apply cross multiplication
H×2a=-b
2aH=-b
In the question you are to find positive b not negative b so you have to take negative b to the left hand side of the equation to become positive b and take 2aH to the right hand side to become -2aH
therefore b=-2aH
Basic method is Synthetic Division and Factor Theorem
Step-by-step explanation:
For higher-degree equations, the question becomes more complicated than others: cubic and quadratic equations can be solved by similar formulas.
Hence, to avoid those circumstances we can use Synthetic Division and Factor theorem to determine the squares of the given polynomial those who have order higher than 2.
21−=2(2−)=2cos(−1)+2 sin(−1)
−1+2=−1(2)=−1(cos2+sin2)=cos2+ sin2
Is the above the correct way to write 21− and −1+2 in the form +? I wasn't sure if I could change Euler's formula to =cos()+sin(), where is a constant.
complex-numbers
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edited Mar 6 '17 at 4:38
Richard Ambler
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asked Mar 6 '17 at 3:34
14wml
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1 Answer
1
No. It is not true that =cos()+sin(). Notice that
1=1≠cos()+sin(),
for example consider this at =0.
As a hint for figuring this out, notice that
+=ln(+)
then recall your rules for logarithms to get this to the form (+)ln().
