Answer:
Option B. $900
Step-by-step explanation:
Let
y ----> the value of the car
x ----> the time in years
we know that
The linear function in slope intercept form is equal to

where
m is the slope or the depreciation rate
b is the y-intercept or initial value of the car
we have
The y-intercept or initial value is equal to


we have the ordered pair (5,500)
substitute the value of x and the value of y of the ordered pair in the linear equation and solve for m


Is negative because is a decreasing function
The linear equation is equal to

therefore
It would depreciate $900 each year.
Answer:
$25,740
Step-by-step explanation:
First, converting R percent to r a decimal
r = R/100 = 5%/100 = 0.05 per year,
then, solving our equation
I = 23400 × 0.05 × 2 = 2340
I = $ 2,340.00
The simple interest accumulated
on a principal of $ 23,400.00
at a rate of 5% per year
for 2 years is $ 2,340.00.
45 + 30 = 15(3 + 2) = 15(5) = 75
Answer: I think it’s 225
Explanation: 1,500 • .15= 225
Write and solve an equation:
Total earnings = $782.75 = s(40 hrs) + 1.5*s*(7 hrs)
Then 782.75 = 40s + 10.5s = 50.5s
Dividing both sides by 50.5: s = 15.5. The attendant's regular hourly wage was $15.50.