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2 years ago

Given: AB=CB, CD=ED, Prove: AB // DE

Mathematics

1 answer:

Fiesta28 [93]2 years ago

3 0

Hey there mate ;)

The answer for proving your question is sent as image. Please check.

Thank you !

Answered by Benjemin

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Using the Factor Theorem, which of the polynomial functions has the zeros 2, radical 3 , and negative radical 3 ? f (x) = x3 – 2

butalik [34]

To solve this question, we use the factor theorem, and using it, the polynomial function is:

$f(x) = x^3 - 2x^2 - 3x + 6$

------------------------------

The factor theorem means that if k is a root of f(x), f(k) = 0.

Thus, applying the factor theorem for this question, we have to choose the function for which: $f(2) = 0, f(\sqrt{3}) = 0, f(-\sqrt{3}) = 0$

------------------------------

Function 1:

$f(x) = x^3 - 2x^2 - 3x + 6$

Testing the values:

$f(2) = 2^3 - 2(2)^2 - 3(2) + 6 = 8 - 8 - 6 + 6 = 0$

$f(\sqrt{3}) = \sqrt{3^3} - 2(\sqrt{3})^2 - 3\sqrt{3} + 6 = \sqrt{3^2\times3} - 6 - 3\sqrt{3} + 6 = 3\sqrt{3} - 3\sqrt{3} = 0$

$f(-\sqrt{3}) = -\sqrt{3^3} - 2(-\sqrt{3})^2 - 3(-\sqrt{3}) + 6 = -\sqrt{3^2\times3} - 6 + 3\sqrt{3} + 6 = -3\sqrt{3} + 3\sqrt{3} = 0$

Thus, since all three conditions are satisfied, $f(x) = x^3 - 2x^2 - 3x + 6$ is the polynomial function.

A similar question is given at brainly.com/question/11378552

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3 years ago

Evaluate the expression for a = 26, b = 10, c = 9, d = 19: a+b-c-d

Anettt [7]

Answer:

Step-by-step explanation:

a+b-c-d

lets substitute the values of a, b, c and d in the equation:

26+10-9-19

so we have:

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3 years ago

A bus is travelli ng with the velo ci ty of 60 km/hr . Pressin g the bra kes sud denly, it is reta rde d to 0.05 m/s2 . How fa r

solong [7]

Step-by-step explanation:

Initial velocity(u) = 60 km/hr = 50/3 m/s

final velocity(v)= 0 (stops at rest)

acceleration(a) = -0.05 m/s²

display (s)=?

v²-u²=2as

0²- (50/3)= 2(-0.05)s

2500/9= 0.1s

s= 25000/9 m

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2 years ago

How many 3/4s are in 3 2/4

MArishka [77]

Answer:

the answer is 3

Step-by-step explanation:

First change the whole number (3) to quaters or fraction

3x $\frac{4}{4}$ = $\frac{12}{4}$

Now, add

$\frac{2}{4}$ + $\frac{12}{4}$ = $\frac{14}{4}$ Since, we have the same common denominator

now divide

14÷4 =3.5 = 3 $\frac{2}{4}$

Therefore, there are 3 of 3/4 with a remainder of $\frac{2}{4}$ in 3 $\frac{2}{4}$ .

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2 years ago

What is the sales tax on a jacket at 750 of the sales tax rate is 7%

SIZIF [17.4K]

Sales tax is $52.50

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3 years ago