Answer:
The second option is the correct answer
The sequence is : 0, -1, -6, -31, -156
Step-by-step explanation:
It is given that,
The recursive formula , an = 5a(n-1) - 1 and a1 = 0
<u>To find a2, a3, a4, a5 </u>
a2 = 5a1 -1 = 5x0 - 1 = -1
a3 = 5a2 - 1 = (5x -1 ) - 1 = - 5 - 1 = -6
a4 = 5a3 - 1 =(5x -6) - 1 = -30 - 1= -31
a5 = 5a4 - 1 = (5 x -31 ) - 1 = -155 -1 = -156
Therefore the resulting sequence is
0, -1, -6, -31 ,-156
the sequence is 0, -1, -6, -31 ,-156 so that would be choice B
Don't really understand the question, but
17 = 1 7/10
1.7 < 1 7/9
1.7 is less than 1 7/9
graph g(x)=1/4 x^2 - 2
You are to replace x with (1/2x) in the expression x^2-2
So you have (1/2x)^2-2
1/4 x^2-2
Graph some points for g(x)=1/4 x^2-2
The vertex is (0,-2) and the parabola is open up.
I would graph 2 more points besides the vertex
x | g(x) ordered pairs to graph
----------- (-1,-1.75) and (0,-2) and (1,-1.75)
-1 -1.75
0 -2
1 -1.75
