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yulyashka [42]
3 years ago
12

Y=3x+18 -12x+4y=-24 linear system of equations

Mathematics
1 answer:
solong [7]3 years ago
7 0

Answer:

Step-by-step explanation:

Use substitution, y=3x+18 so -12x+4(3x+18)=-24. From here you can try to solve for x

-12x+12x+72=-24

The xs cancel, which leaves you with 72=-24

Since 72 cannot equal -24 there is no answer to this system of equations

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Is -0.25 rattional or irrational
sattari [20]
The answer is rational
3 0
2 years ago
Caroline is trying to earn money to pay for her field trip by doing odd jobs around the house. She needs to raise more than $35
Alenkasestr [34]

The inequality that represents how much money Caroline needs to earn will be m>35.

In this case, Caroline needs an amount that's greater than $35, therefore, the amount must be greater than $35

From the options given, the correct inequality will be m>35. This means m is greater than $35.

Read related link on:

brainly.com/question/24751617

8 0
2 years ago
How do I put y=90-15x in standard form
lisabon 2012 [21]

The standard form: Ax + By = C


y = 90 - 15x     <em>add 15x to both sides</em>

<h3>15x + y = 90</h3>
8 0
3 years ago
Choose the correct simplification of the expression (−2x + 8y)(9x − 3y).
Romashka-Z-Leto [24]
For these kinds of expressions use FOIL (first, outside, inside, last).

-2x • 9x = -18x^2
-2x • -3y = 6xy
8y • 9x = 72 xy
8y • -3y = -24y^2

Now combine them all:

-18x^2 + 78xy - 24y^2
6 0
3 years ago
Read 2 more answers
Multiply. Check picture.
VashaNatasha [74]

The answer is 3x^4-13x^3-x^2-11x+6.

Solution:

Use algebraic identity: a^m\times a^n=a^{m+n}

For example: x^2\times x=x^{2+1}=x^3

Given expression (x^2-5x+2) and (3x^2+2x+3).

To multiply these equations.

(x^2-5x+2)\times(3x^2+2x+3)

             =x^2(3x^2+2x+3)-5x(3x^2+2x+3)+2(3x^2+2x+3)

             =(3x^4+2x^3+3x^2)+(-15x^3-10x^2-15x)+(6x^2+4x+6)

             =3x^4+2x^3+3x^2-15x^3-10x^2-15x+6x^2+4x+6

Combine like terms together.

             =3x^4+(2x^3-15x^3)+(3x^2-10x^2+6x^2)-15x+4x+6

             =3x^4-13x^3-x^2-11x+6

(x^2-5x+2)\times(3x^2+2x+3)=3x^4-13x^3-x^2-11x+6

Hence the answer is 3x^4-13x^3-x^2-11x+6.

3 0
3 years ago
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