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wel
3 years ago
8

What is the standard form of 0.00015​

Mathematics
2 answers:
SSSSS [86.1K]3 years ago
7 0
Hi the answer is
1.5 x 10^-4

mark as brainliest if it’s helpful
Goshia [24]3 years ago
5 0
<h2>Answer: 1.5</h2>

<h3>hope it help you :)))))))</h3>
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IRISSAK [1]
2x= -8
2x/2=-8/2
X= -4
6 0
3 years ago
Find the radius of a circle whose circumference is 31.4 centimeters. Approximate Π as 3.14.
AnnyKZ [126]
Circumference is Diameter * 3.14

so D * 3.14 = 31.4

31.4 / 3.14 = 10 so the diameter is 10.

the radius is half of the diameter so radius = 5 centimeters.
4 0
3 years ago
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Which name correctly classifies this triangle? A. right B. obtuse C. acute
sergejj [24]
Hello there!

The would be a (right angle) because this angle is not greater than, or less than 90°.

Your correct answer would be the first option. (right angle).
7 0
3 years ago
Please help Really confusied dont do the last 2 at the bottom
Helen [10]
Number one or 2? so i can help you
6 0
3 years ago
Type the correct answer in each box. If necessary, round your answers to the nearest hundredth.
disa [49]

Answer:

Perimeter = 32.44 units

Area = 30 square units

Step-by-step explanation:

Given

Vertices

A(2,8), B(16,2) and C(6,2)

WE have to determine the lengths of all sides before finding the perimeter and area.

The formula of modulus is:

d = \sqrt{(x_{2}- x_{1})^{2} +(y_{2}-y_{1})^{2}}\\AB=\sqrt{(16-2)^{2} +(2-8)^{2}}\\=\sqrt{(14)^{2} +(-6)^{2}}\\=\sqrt{196+36}\\ =\sqrt{232}\\=15.23\\\\BC=\sqrt{(6-16)^{2} +(2-2)^{2}}\\=\sqrt{(-10)^{2} +(0)^{2}}\\=\sqrt{100+0}\\ =\sqrt{100}\\=10\\\\AC=\sqrt{(6-2)^{2} +(2-8)^{2}}\\=\sqrt{(4)^{2} +(-6)^{2}}\\=\sqrt{16+36}\\ =\sqrt{52}\\=7.21\\\\

So the perimeter is:

Perimeter=AB+BC+AC\\=15.23+10+7.21\\=32.44\ units

Using hero's formula,

s=\frac{perimeter}{2}\\s=\frac{32.44}{2}\\ s=16.22\\Area=\sqrt{s(s-a)(s-b)(s-c)}\\=\sqrt{16.22(16.22-15.23)(16.22-10)(16.22-7.21)}\\=\sqrt{(16.22)(0.99)(6.22)(9.01)}\\=\sqrt{899.91}\\=29.99\ square\ units

Rounding off will give us 30 square units ..

4 0
3 years ago
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