1. 12/5
2. 24/10
3. 48/20
4. 96/40
Greatest to least
23.72, 23.697, 22.8
hope this helps
23.72 is greater than 23.697 by 0.023
Given that
the weight of football players is distributed with a mean of 200 pounds and a standard deviation of 25 pounds.
And we need to find What is the minimum weight of the middle 95% of the players?
Explanation -
Using the Empirical Rule, 95% of the distribution will fall within 2 times of the standard deviation from the mean.
Two standard deviations = 2 x 25 pounds = 50 pounds
So the minimum weight = 200 pounds - 50 pounds = 150 pounds
Hence the final answer is 150 pounds.
