All categories

3 years ago

Find the first, fourth, and eighth terms of the sequence. A(n)=-2 × 2^N-1

1 answer:

7 0

an=(−2x)(2−1)Step 1: Divide both sides by n.ann=−xna=−xnAnswer:a=−xn

Read more about calculators here:

brainly.com/question/164042

#SPJ1

5 0

2 years ago

Determine which method would be more efficient for solving: Rewriting and using the distributive property or dividing. Solve eac

liq [111]

Answer:

A. x = 3.03

B. x = 4/3

Step-by-step explanation:

A. 2000 (x-0.03) = 6000 is quickly simplified byu dividing both sides by 2000:

(x - 0.03) = 3. Removing the parentheses, we get: x = -0.03 = 3, or x = 3.03.

B. The distributive property is the faster method here. We determine that the LCD is 12 and multiply both sides of this equation 1/4 (4+x) = 4/3 by 12:

3(4 + x) = 16

and then carry out the indicated multiplication: 12 + 3x = 16, or

3x = 4, or x = 4/3

7 0

2 years ago

In 2015, there were roughly 1x10^6 high school football players and 2x10^3 professional football players in the United States.

melisa1 [442]

Answer:

500.

Step-by-step explanation:

(1 * 10^6) / (2 * 10^3)

= 1/2 * 10^6/10^3

= 0.5 * 10^3

= 5 * 10^2

= 500.

5 0

3 years ago

1. Two object accumulated a charge of

In-s [12.5K]

Answer:

The magnitude of the electric force between these two objects

will be: 181.274 N.

i.e. F $=181.274$ N

Step-by-step explanation:

Two object accumulated a charge of 4.5 μC and another a charge of 2.8 μC.

q₁ = 4.5 μC = 4.5 × 10⁻⁶ C

q₂ = 2.8 μC = 2.8 × 10⁻⁶ C

separated distance = d = 2.5 cm

Calculating the magnitude of the force between two charged objects using the formula:

$F = \frac{1}{4\pi \epsilon_0}\frac{q_1 q_2}{r^2}$

$=\:\frac{4.5\times \:\:10^{-6}\:\times \:\:2.8\:\times \:\:10^{-6}}{4\:\times \:\left(3.14\right)\:\times \:\left(8.85\times \:10^{-12}\right)\times \left(2.5\times \:\:10^{-2}\right)^2}$

$=\frac{10^{-12}\times \:12.6}{10^{-12}\times \:4\times \:8.85\pi \left(10^{-2}\times \:2.5\right)^2}$ ∵ $4.5\times \:10^{-6}\times \:2.8\times \:10^{-6}=10^{-12}\times \:12.6$

$=\frac{10^{-12}\times \:12.6}{10^{-12}\times \:35.4\pi \left(10^{-2}\times \:2.5\right)^2}$ ∵ $\mathrm{Multiply\:the\:numbers:}\:4\times \:8.85=35.4$