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3 years ago

Pleaseeee help i think its easy but I don't know

Mathematics

2 answers:

Afina-wow [57]3 years ago

7 0

Answer:

12: 32

18: 48

27: 72

scoray [572]3 years ago

3 0

Answer:

12:24

18:48

27:81

Step-by-step explanation:

12 pound is going to be 8 times 3 which is 24

18 pounds is going to be 8 times 6 which is 48

27 pounds is goings to be 8 times 9 which is 81

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Volume = 154 cm cubic

zheka24 [161]

Cylinder Volume

Level : JHS

V = hπr²

154 cm³ = 16 cm × 3.14 × r²

154 cm³ = 50.28 cm × r²

r² = 154 cm³ : 50.28 cm

r² = 3.0625 cm²

r = 1.75 cm

d = 2r

d = 2 × 1.75 cm

d = 3.5 cm

So, the diameter of the Cylinder is 3.5 cm

#LearnWithEXO

8 0

3 years ago

Which of the following is not one of the 8th roots of unity?

Anika [276]

Answer:

1+i

Step-by-step explanation:

To find the 8th roots of unity, you have to find the trigonometric form of unity.

1. Since $z=1=1+0\cdot i,$ then

$Rez=1,\\ \\Im z=0$

and

$|z|=\sqrt{1^2+0^2}=1,\\ \\\\\cos\varphi =\dfrac{Rez}{|z|}=\dfrac{1}{1}=1,\\ \\\sin\varphi =\dfrac{Imz}{|z|}=\dfrac{0}{1}=0.$

This gives you $\varphi=0.$

Thus,

$z=1\cdot(\cos 0+i\sin 0).$

2. The 8th roots can be calculated using following formula:

$\sqrt[8]{z}=\{\sqrt[8]{|z|} (\cos\dfrac{\varphi+2\pi k}{8}+i\sin \dfrac{\varphi+2\pi k}{8}), k=0,\ 1,\dots,7\}.$

Now

at k=0, $z_0=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 0}{8}+i\sin \dfrac{0+2\pi \cdot 0}{8})=1\cdot (1+0\cdot i)=1;$

at k=1, $z_1=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 1}{8}+i\sin \dfrac{0+2\pi \cdot 1}{8})=1\cdot (\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2})=\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2};$

at k=2, $z_2=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 2}{8}+i\sin \dfrac{0+2\pi \cdot 2}{8})=1\cdot (0+1\cdot i)=i;$

at k=3, $z_3=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 3}{8}+i\sin \dfrac{0+2\pi \cdot 3}{8})=1\cdot (-\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2})=-\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2};$

at k=4, $z_4=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 4}{8}+i\sin \dfrac{0+2\pi \cdot 4}{8})=1\cdot (-1+0\cdot i)=-1;$

at k=5, $z_5=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 5}{8}+i\sin \dfrac{0+2\pi \cdot 5}{8})=1\cdot (-\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2})=-\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2};$

at k=6, $z_6=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 6}{8}+i\sin \dfrac{0+2\pi \cdot 6}{8})=1\cdot (0-1\cdot i)=-i;$

at k=7, $z_7=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 7}{8}+i\sin \dfrac{0+2\pi \cdot 7}{8})=1\cdot (\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2})=\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2};$

The 8th roots are

$\{1,\ \dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2},\ i, -\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2},\ -1, -\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2},\ -i,\ \dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2}\}.$

Option C is icncorrect.

5 0

3 years ago

Find the slope of the line that passes through each pair of points.

kotegsom [21]

6. m=2
7. m=3
8. m=0
Hope it help

6 0

3 years ago

Numbers with the same absolute value are__________

Radda [10]

They are either the same, or opposite number.

4 0

4 years ago

Read 2 more answers

Solve the equation 4n2 − 16n − 84 = 0 by completing the square.

melomori [17]

4n² - 16n - 84 = 0

Multiply both sides by 1/4 :

n² - 4n - 21 = 0

Add 21 to both sides:

n² - 4n = 21

Complete the square by adding 4 to both sides:

n² - 4n + 4 = 25

(n - 2)² = 25

Solve for n :

n - 2 = ± √25

n - 2 = ± 5

n = 2 ± 5

Then n = 2 + 5 = 7 or n = 2 - 5 = -3.

8 0

2 years ago