Let n be the 40%, and 100-n be the 10%. Then:
.4n+.1(100-n)=.22(100)
.3n+10=22
.3n=12
n=40
The candy distributor needs 40kg of 40%, and 60kg of 10%
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4 0

4 years ago

I will give brainlist!

Ilya [14]

Answer:

The length of x is 4

Step-by-step explanation:

The scale factor is Large/small where 10/8 which is DF/AC.

THE SCALE factor is 5/4.

To find the length of X is in AB we use the scale factor 5/4 and the corresponding DE.

5/4 = DE/AB

5/4 = 5/X

X = 4

To find Y in EF will use the corresponding BC which is 6.

5/4 = EF/BC

5/4 = Y/6

Y= 7.5

info: use CORRESPONDING ABC AND DEF .

3 0

3 years ago

Given f'(x) = (x-4)(4-2x), find the x-coordinate for relative maximum on the graph of f(x)

antiseptic1488 [7]

Answer:

The coordinate of the relative maximum is x=4.

Step-by-step explanation:

Given that the derivative of the function $f(x)$ is $f'(x) = (x-4)(4-2x)$ , the maxima and minima or the critical points can be found where $f'(x)=0,$ that is:

$f'(x) = (x-4)(4-2x)=0.$

The solutions to this equation are $x=4$ and $x=2.$

Now, if the second derivative $f''(x)$ for a function $f(x)$ is negative at a critical point, then the critical point is the relative maximum.

Therefore we want to see at which of the two critical points is $f''(x)$ negative. The second derivative is:

$\frac{\mathrm{d f'(x)}}{\mathrm{d}x}=f''(x)=-4(x-3).$

Now $f''(4)$ is $-4$ , and $f''(2)$ is $+4$ , therefore we deduce that the relative maxium is located at $x=4$ , because there the second derivative $f''(x)$ is negative.

4 0

3 years ago