By pythagorean theorem

a^2+b^2=c^2

We can find that PL is 12.65

and then by altitude theorem

MA*LA=PA^2

we can find the value of MA

12MA=16

MA=1.33

then by the pythagorean theorem

we can use to find PM

MA^2+PA^2=PM^2

so PM=4.22

then to find the are you multiply length by width

PM*PL

12.65*4.22

So the area is 53.38

8 0

3 years ago

A spring has natural length 24 cm. Compare the work W1 done in stretching the spring from 24 cm to 34 cm with the work W2 done i

Scilla [17]

Answer:

From the analysis W1=W2.

they are directly related

Step-by-step explanation:

the work-done in stretching a spring can be expressed as

$W=\frac{1}{2}kx^2$

where k= spring constant

x= change on length of spring

Hence for W1

Given data

x= 34-24= 10 cm

solving in terms of k we have

$W=\frac{1}{2}k*10^2\\\W=\frac{1}{2}k*100\\\W=50k$

Hence for W2

Given data

x= 44-34= 10 cm

solving in terms of k we have

$W=\frac{1}{2}k*10^2\\\ W=\frac{1}{2}k*100\\\ W=50k$

4 0

3 years ago