Answer:
1.26 feets
Step-by-step explanation:
Given the following :
Vertex (0, 0)
Focus of reflector = 6 feets
Extension = 5.5 feets
Equation to obtain conic section of a parabola:
(x - h)² = 4p(y - k)
Vertex (0, 0)
h =0 ; k = 0, p = 6, x = 5.5
(5.5 - 0)² = 4*6(y - 0)
30.25 - 0 = 24(y - 0)
30.25 = 24y
y = 30.25 / 24
y = 1.26
Hence, depth of reflector = 1.26 feets
Answer:
im evil
Step-by-step explanation:
i already know it
The line integral is the path of the function along a line having a continuous value.
The integral solved gives the value 111.
The given question is
where C is the line from (1, 0, 0) to (4, 1, 3)
Here
x→ 1⇒ 4
y→ 0⇒1
z→ 0⇒ 3
Let t be defined be the range 0≤ t ≤ 1
Then x= 4t+1 : dx= 4dt
y= t ": dy= dt
z= 3t : dz= 3dt
Putting the values
= [36(1)²- 36(0)²]+ 3 [16(1)² +1+8(1)] - 3 [16(0)² +1+8(0)] + [3(1)²- 3(0)² ]
= 36 +75-3+3
= 111
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Answer:
m∠BOC = 40°
Step-by-step explanation:
Given O A ‾ ⊥ O C ‾ OA ⊥ OC m∠BOC=6x−6 ∘
m∠AOB=5x+8 ∘
Find m ∠ B O C:
This means that: m∠BOC and m∠AOC intersect at a right angle.
Hence:
m∠BOC + m∠AOC = 90°
Step 1
Solving for x
6x - 6 + 5x + 8 = 90°
11x -2 = 90°
11x = 90 - 2
11x = 88
x = 88/11
x = 8
Step 2
Solving for m∠BOC
m∠BOC = 6x - 8
m∠BOC = 6(8) - 8
= 48 - 8
= 40°
Answer:
8.26
Step-by-step explanation: