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KonstantinChe [14]

3 years ago

10

Find f(-2) for f(x)=3•2^x

1 answer:

8_murik_8 [283]3 years ago

5 0

Answer:

0.75 or 3/4

Step-by-step explanation:

f(-2) = 3•2^-2

f(-2) = 3•0.25

f(-2) = 0.75 or 3/4

Hope this helps! :)

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Find the range of the function

Zina [86]

Answer:

Write down y=f(x) and then solve the equation for x, giving something of the form x=g(y).

Find the domain of g(y), and this will be the range of f(x).

If you can't seem to solve for x, then try graphing the function to find the range.

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3 years ago

Stolb23 [73]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

Let's solve for value of values of x and y ~

According to Angle sum property of triangles :

$\qquad \sf \dashrightarrow \: 70 \degree + 58\degree + x = 180\degree$

$\qquad \sf \dashrightarrow \: x\degree + 128\degree = 180\degree$

$\qquad \sf \dashrightarrow \:x = 180\degree - 128\degree$

$\qquad \sf \dashrightarrow \: x = 52\degree$

Now, solve for y ~

$\qquad \sf \dashrightarrow \: 70\degree + 49\degree + y = 180\degree$

$\qquad \sf \dashrightarrow \: y + 119 = 180\degree$

$\qquad \sf \dashrightarrow \: y = 180 - 119\degree$

$\qquad \sf \dashrightarrow \: y = 61 \degree$

Now, by the results we got, we can conclude that :

The two triangles are not similar because 70 + 58 + x = 180 means x = 52° and 70 + 49 + y=180 means y = 61°

8 0

2 years ago

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38 kg of onions cost $144.40. how much would 49 kg cost?

Lerok [7]

Answer:

$186.2

Step-by-step explanation:

38 kg costs $144.40

∴ 1 kg costs = $\frac{144.40}{38}$ = $3.8

49 kg costs = 3.8 x 49

= $186.2

7 0

1 year ago

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How many solutions does the equation x_1 +x_2+x_3+x_4+x_5=21 have where x_1, x_2, x_3, x_4, and x_5 are nonnegative integers and

omeli [17]

Step-by-step explanation:

$x_{1} + x_{2} + x_{3} + x_{4} + x_{5} = 21\\$ (given)

Let us consider :

$x_{1}$ = $t_{1} + 1$

$x_{2}$ = $t_{2}$

$x_{3}$ = $t_{3}$

$x_{4}$ = $t_{4}$

$x_{5}$ = $t_{5}$

Now, by substituting the above considerations in the above equation, we get:

$t_{1} + 1 + t_{2} + t_{3} + t_{4} + t_{5} = 21\\$

$t_{1} + t_{2} + t_{3} + t_{4} + t_{5} = 20\\$

where,

$t_{i}$ $\geq$ 1

then it follows

n = 20

r = 4

then no. of solutions for the eqn = $_{r}^{n + r}\textrm{C}$

= $_{4}^{24}\textrm{C}$

= 10626

Answer :

no. of solutions for the eqn 10626

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What does h(40) = 1400 mean in terms of the problem

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The answer is B because 40 is under hours of training and 1400 is under monthly pay

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