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slavikrds [6]
2 years ago
10

Which of the following is not a proportion?

Mathematics
2 answers:
tia_tia [17]2 years ago
5 0
I believe it’ll be 4/10 = 12/20
Luda [366]2 years ago
4 0
4/10=12/20

Because if you divide 12/20 by two you get 6/10 Nd it’s not equal to 4/10
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Is it scalene isosceles or equilateral then write acute obtuse or right thx
almond37 [142]
It's scalene because it has different sides and obtuse because root 40²+30²=50
110>50
4 0
3 years ago
How do u put 72 7/10 into decimal?
NNADVOKAT [17]

Answer:

72.7

Step-by-step explanation:

First multiply 72 by 10

because 72 is 72 10s, making it a whole number.

then add 720 (72 times 10) to 7.

then all of that over 10.

then just divide.

727/10

72.7

this is what you do for all mixed numbers like that one.

7 0
3 years ago
Read 2 more answers
What is the image of (0,-8)(0,−8) after a reflection over the line y=-xy=−x?
AnnZ [28]

Answer:

(8, 0 )

Step-by-step explanation:

under a reflection in the line y = - x

a point (x, y ) → (- y, - x ) , then

(0, - 8 ) → (8, 0 )

5 0
1 year ago
A school P is 16km due west of a school Q. what is the bearing of Q from P​
Irina-Kira [14]

Answer:

16Km due east of school P

Step-by-step explanation:

Given

A school P is 16km due west of a school Q

Thus, we can say that distance PQ = 16 km.

________________________________

now we have to find  the bearing of Q from P​

As distance is same

distance PQ = distance QP

Thus,

Distance will remain same of 16 km.

For direction,

If Q is west of P, then P will be east of QP------------------>Q

as shown in figure P is west of Q,

now from point P , Q is west P.

Thus,

Bearing of  School Q from P is 16Km due east of school P

7 0
3 years ago
Pythagoras question plz help
motikmotik
From the two right triangles, you can write the following equations using the Pythagorean theorem. Let's call that shared leg in the middle "y"

y^2 + b^2 = a^2
y^2 + c^2 = x^2


y^2 + b^2 = a^2
re-write this to get "y" alone for substitution.
y^2 = a^2 - b^2
substitute (a^2 - b^2) for y^2 in the other equation. y^2 + c^2 = x^2

a^2 - b^2 + c^2 = x^2

Now put in the values given for a,b,c to solve for x

(7.1)^2 - (5.6)^2 + (5.7)^2 = x^2
51.54 = x^2
square root
7.2 = x


6 0
3 years ago
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