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2 years ago

Ron bought a keychain for $7 and 3 t-shirts. He spent a total of $37. How much does each t-shirt cost?

Mathematics

1 answer:

White raven [17]2 years ago

4 0

Answer:

$10

Step-by-step explanation:

Subtract the price of the keychain, $7, from the total to find the price of the 3 t-shirts:

$37 - $7 = $30

The 3 t-shirts cost a total of $30.

We assume all t-shirts have the same price.

price of 1 t-shirt = $30/3 = $10

Answer: $10

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If yvaries inversely as x and y=18 when x=2, find y when x=4

Sergio039 [100]

I believe the answer would be 36.

Hope this helped you. ;}

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3 years ago

Is the statement below always,sometimes,or never true? Give at least two examples to support your reasoning. The LCM of two numb

Natali5045456 [20]

Answer:

True for Co-Prime Numbers
False for Non Co-Prime Numbers

Step-by-step explanation:

<u>STATEMENT:</u> The LCM of two numbers is the product of the two numbers.

This statement is not true except if the two numbers are co-prime numbers.

Two integers a and b are said to be co-prime if the only positive integer that divides both of them is 1.

<u>Example: </u>

Given the numbers 4 and 7, the only integer that divides them is 1, therefore they are co-prime numbers and their LCM is their product 28.

However, consider the number 4 and 8. 1,2 and 4 divides both numbers, they are not co-prime, Their LCM is 8 which is not the product of the numbers.

3 0

2 years ago

In Applied Life Data Analysis (Wiley, 1982), Wayne Nelson presents the breakdown time of an insulating fluid between electrodes

ale4655 [162]

Answer:

The sample mean is $\bar{x}=14.371$ min.

The sample standard deviation is $\sigma = 18.889$ min.

Step-by-step explanation:

We have the following data set:

$\begin{array}{cccccccc}0.15&0.82&0.81&1.44&2.70&3.28&4.00&4.70\\4.96&6.49&7.25&8.03&8.40&12.15&31.89&32.47\\33.79&36.80&72.92&&&&&\end{array}$

The mean of a data set is commonly known as the average. You find the mean by taking the sum of all the data values and dividing that sum by the total number of data values.

The formula for the mean of a sample is

$\bar{x} = \frac{{\sum}x}{n}$

where, $n$ is the number of values in the data set.

$\bar{x}=\frac{0.15+0.82+0.81+1.44+2.7+3.28+4+4.7+4.96+6.49+7.25+8.03+8.4+12.15+31.89+32.47+33.79+36.80+72.92}{19}\\\\\bar{x}=14.371$

The standard deviation measures how close the set of data is to the mean value of the data set. If data set have high standard deviation than the values are spread out very much. If data set have small standard deviation the data points are very close to the mean.

To find standard deviation we use the following formula

$\sigma = \sqrt{ \frac{ \sum{\left(x_i - \overline{x}\right)^2 }}{n-1} }$