To compute the perimeter of a rectangle, you add the length, l , and width, w , and double this sum.
2 answers:
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Answer:
Step-by-step explanation:
Given that the owner of a motel has 2900 m of fencing and wants to enclose a rectangular plot of land that borders a straight highway.
Fencing is used for 2times length and 1 width if highway side is taken as width
So we have 2l+w = 2900
Or w = 2900-2l
Area of the rectangular region = lw
Use derivative test to find the maximum
So maximum when I derivative =0
i.e when
Largest area = A(725)
=
1051250 sqm is area maximum