In order to understand this question, one needs to understand the construction first. After creating POQ, Meg picks a radius r and makes a circle around O. There are 2 points where the circle meets the triangle. Then, she meets another radius and she makes a circle of radius s around each of the points on the triangle. The two circles cross at one point, as can be seen in the figure. Let's name the first two points A and B and let's name the last point S. We have that for the triangles OAS, OBS we have OA=OB=r, BS=AS=s and that OS is common to both. Thus by the S-S-S triangle equality theorem, the triangles are equal. Hence for the angles AOS=BOS, namely POS=QOS. Since POQ=POS+QOS, we have that POS has to be half of POQ. The only consistent choice is the third one, POS=20 degrees and POQ=40 degrees.
Answer:
note :
The equation of a linear function in point-slope form is y – y1 = m(x – x1)
The point is A (x1 , y1)
Step-by-step explanation:
in this exercice : y - 4 = 5 +(1/2)x
y - 4 = 0.5 ( x - 5/0.5)
y - 4 = 0.5( x - 10).....
note : the standard forme is : y = ax +b
in this exercice : y = (1/2)x+9
X^2 - 5x - 24
(X - 8)(x + 3)
X = 8 and x = -3
Therefore, the other solution is -3.
