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kondor19780726 [428]
3 years ago
12

What are the coordinates of point BBB on \overline{AC} AC start overline, A, C, end overline such that the ratio of ABABA, B to

BCBCB, C is 2:32:32, colon, 3?
A) 2 1/5, 1/5
B) 2 1/4, 1/4
C) 3 3/4, 3/4
D) 3 3/5, 3/5
Mathematics
2 answers:
nikdorinn [45]3 years ago
5 0

Answer:

Stepb-by-step explanation:

Nady [450]3 years ago
3 0
I think it’s gonna be C
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FACTORIZE<br>A(X)=(2+3x)(-x+7)(-2+3x)(2x+1)​​
frozen [14]

Answer:

That's the ans.

Step-by-step explanation:

I screentshot the ans.

5 0
3 years ago
Write the following inequality in slope intercept form
yarga [219]
The answer would be C) y</=x-14

The steps to get this are:

1) Add 5y to both sides to remove the negative 5y
2) Subtract 70 from both sides to isolate 5y
3) Divide everything by 5 to simplify

That's how to get the answer. Hope this helps
6 0
3 years ago
If an individual saves $5,700 and elects to place the total dollar amount into a savings account earning 2.75% APR compounded mo
Naddika [18.5K]

Answer:

$7,925.53

Step-by-step explanation:

We'll have to use the compound interest formula: A = P(1 + r/n)ⁿˣ

A = final amount (?)

P = starting amount (5700)

r = rate

n = times applied (12 since its monthly and there 12 months in a year)

x = years (12)

A = 5700(1 + 0.0275/12)¹⁴⁴

A = 7925.525498629932

7 0
3 years ago
Is the relationship between 7,742 and 7,785 different in anyway?
timurjin [86]
Yes Because 7,785 is greater than 7,742.
5 0
3 years ago
Use linear approximation to approximate √25.3 as follows.
Sophie [7]

The idea is to use the tangent line to f(x)=\sqrt x at x=25 in order to approximate f(25.3)=\sqrt{25.3}.

We have

f(x)=\sqrt x\implies f(25)=\sqrt{25}=5

f'(x)=\dfrac1{2\sqrt x}\implies f'(25)=\dfrac1{10}

so the linear approximation to f(x) is

L(x)=f(5)+f'(5)(x-5)=5+\dfrac{x-5}{10}=\dfrac x{10}+\dfrac92

Hence m=\frac1{10} and b=\frac92.

Then

f(25.3)\approx L(25.3)=\dfrac{25.3}{10}+\dfrac92=\boxed{7.03}

4 0
3 years ago
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