Question

Fe(s) + S(s) → FeS(s)

Answer 1

The mass of FeS formed : 11.97 g

Further explanation

Reaction

Fe(s) + S(s) → FeS(s)

mass Fe=7.62 g

mol Fe(MW=56 g/mol) :

$\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{7.62}{56}\\\\mol=0.136$

mass S=8.67 g

mol S(MW=32 g/mol) :

$\tt mol=\dfrac{8.67}{32}=0.271$

Limiting reactant : smaller ratio(mol:coefficient) ⇒coefficient=1

Fe : S =0.136 : 0.271⇒Fe limiting(smaller), S excess

Mol FeS based on Fe , so mol FeS=0.136

Mass FeS(MW=88 g/mol) :

$\tt mass=mol\times MW\\\\mass=0.136\times 88=11.97~g$