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Marina CMI [18]
3 years ago
6

Fe(s) + S(s) → FeS(s)

Chemistry
1 answer:
insens350 [35]3 years ago
5 0

The mass of FeS formed : 11.97 g

<h3>Further explanation</h3>

Reaction

Fe(s) + S(s) → FeS(s)

mass Fe=7.62 g

mol Fe(MW=56 g/mol) :

\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{7.62}{56}\\\\mol=0.136

mass S=8.67 g

mol S(MW=32 g/mol) :

\tt mol=\dfrac{8.67}{32}=0.271

Limiting reactant : smaller ratio(mol:coefficient) ⇒coefficient=1

Fe : S =0.136 : 0.271⇒Fe limiting(smaller), S excess

Mol FeS based on Fe , so mol FeS=0.136

Mass FeS(MW=88 g/mol) :

\tt mass=mol\times MW\\\\mass=0.136\times 88=11.97~g

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