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Dmitry [639]
3 years ago
9

If x is equal to 48 and y is equal to 12 then what is the value of x-4y?

Mathematics
2 answers:
Katena32 [7]3 years ago
7 0

Answer:

0

Step-by-step explanation:

48 - 4(12)

48 - 48 = 0

Inessa05 [86]3 years ago
5 0

Answer:

The value of x - 4y would be 0.

Step-by-step explanation:

Since x is equivalent to 48, and y is equivalent to 12, you need to replace x and y with those values in order to solve the expression. x-4y = 48 - 4 * 12 = 48 - 48 = 0, so that is the correct answer.

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The harbormaster wants to place buoys where the river bottom is 20 feet below the surface of the water. Complete the absolute va
Natalija [7]

Answer:

The answer is below

Step-by-step explanation:

The bottom of a river makes a V-shape that can be modeled with the absolute value function, d(h) = ⅕ ⎜h − 240⎟ − 48, where d is the depth of the river bottom (in feet) and h is the horizontal distance to the left-hand shore (in feet). A ship risks running aground if the bottom of its keel (its lowest point under the water) reaches down to the river bottom. Suppose you are the harbormaster and you want to place buoys where the river bottom is 20 feet below the surface. Complete the absolute value equation to find the horizontal distance from the left shore at which the buoys should be placed

Answer:

To solve the problem, the depth of the water would be equated to the position of the river bottom.

d(h)=river \ bottom\\\\The \ river \ bottom=-20\ feet(below)\\\\d(h) = -20\\\\\frac{1}{5}|h-240|-48=-20\\ \\\frac{1}{5}|h-240|=-20+48\\\\\frac{1}{5}|h-240|=28\\\\|h-240|=28*5\\\\|h-240|=140\\\\h-240=140\ or\ h-240=-140\\\\h=140+240\ or\ h=-140+240\\\\h=380\ or\ h=100\\\\The\ buoys\ should\ be\ placed\ at\ 100\ feet\ and\ 380\ feet\ from\ left-hand\ shore

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4 years ago
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