Answer:
5, 7, 9
Step-by-step explanation:
Using the information given we get:



<em>Add 7 to both sides</em>

<em>Subtract 2x from both sides</em>

<em>Divide both sides by 3</em>

Using these equations:

and

We get:

Answer:
Given: BD is an altitude of △ABC .
Prove: sinA/a=sinC/c
Triangle ABC with an altitude BD where D is on side AC. Side AC is also labeled as small b. Side AB is also labeled as small c. Side BC is also labeled as small a. Altitude BD is labeled as small h.
Statement Reason
BD is an altitude of △ABC .
Given △ABD and △CBD are right triangles. (Definition of right triangle)
sinA=h/c and sinC=h/a
Cross multiplying, we have
csinA=h and asinC=h
(If a=b and a=c, then b=c)
csinA=asinC
csinA/ac=asinC/ac (Division Property of Equality)
sinA/a=sinC/c
This rule is known as the Sine Rule.
Definition of supplementary angles. Hope this helps. Can you mark me as brainliest if you can? I really appreciate it!
C: Moved down and to the left