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ladessa [460]
4 years ago
15

Which answer is in slope-intercept form for the given equation?

Mathematics
1 answer:
zhuklara [117]4 years ago
6 0

The slope-intercept form:

y = mx + b

m - slope

b - y-intercept

Answer:

B. y = 4/9x + 4

slope = 4/9, y-intercept = 4

D. y = -4/9x - 4

slope = -4/9, y-intercept = -4

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Consider two markets: the market for cat food and the market for dog food. The initial equilibrium for both markets is the same,
umka21 [38]

Answer:

elasticity supply of dog food = 2.61

elasticity supply of cat food = 1.71

Step-by-step explanation:

The midpoint formula for elasticity is:

Elasticity = \frac{(Q2-Q1)/[(Q2+Q1)/2]}{(P2-P1)/[(P2+P1)/2]}

Point 1: Q = 39.0 and P = 5.50

Point 2: Q = 101.0 and P = 7.75

Elasticity\ supply\ of\ dog\ food = \frac{(101.0-39.0)/[101.0+39.0)/2]}{(7.75-5.50)/[(7.75+5.50)/2]}=2.61

Doing the same for the cat food:

Elasticity\ supply\ of\ cat\ food = \frac{(71.0-39.0)/[71.0+39.0)/2]}{(7.75-5.50)/[(7.75+5.50)/2]}=1.71

4 0
4 years ago
I NEED HELP ASAP!!!!!!!!!!!!!!!!
Snowcat [4.5K]

Answer:

1/6

Step-by-step explanation:

If you divide the fractions to decimals 1/6 equals .16 which is closest to 0

7 0
3 years ago
Read 2 more answers
Ian​'s car can go 93 miles on 3 gallons of gas. During a drive, last​ weekend, Ian used 8 gallons of gas. How far did Ian ​drive
Anuta_ua [19.1K]

Answer:248

Step-by-step explanation:

First you need to find the unit rate by dividing 93 by 3 which would be 31 then take that number (which is how many miles for one gallon) and multiply it by 8 which would get you 248( if you need this as an equation here 93\3= 31 31*8 = 248). If they gave you the distance instead you would have had to divide by 31 instead of using multiplication. Hope this helps!

5 0
3 years ago
if pentagon ABCDE is rotated 180 degrees around the origin to create pentagon A’B’C’D’E, what is the ordered pair of point C?
ivanzaharov [21]

How the question has been worded makes me think the answer is (2,5)

4 0
4 years ago
Read 2 more answers
A 5.8-ft-tall person walks away from a 9-ft lamppost at a constant rate of 3.4 ft/sec. What is the rate that the tip of the pers
Dovator [93]

Answer:

9.56 ft/sec

Step-by-step explanation:

We are told that a 5.8-ft-tall person walks away from a 9-ft lamppost at a constant rate of 3.4 ft/sec.

I've attached an image showing  triangle that depicts this;

Thus; dx/dt = 3.4 ft/sec

From the attached image and using principle of similar triangles, we can say that;

9/y = 5.8/(y - x)

9(y - x) = 5.8y

9y - 9x = 5.8y

9y - 5.8y = 9x

3.2y = 9x

y = 9x/3.2

dy/dx = 9/3.2

Now, to find how fast the tip of the shadow is moving away from the lamp post, it is;

dy/dt = dy/dx × dx/dt

dy/dt = (9/3.2) × 3.4

dy/dt = 9.5625 ft/s ≈ 9.56 ft/sec

5 0
3 years ago
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