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Nata [24]
3 years ago
7

F(x)=2x^3+2x-3 g(x)=-.5[x-4] what is the y value when f(x) = g(x)?

Mathematics
1 answer:
Charra [1.4K]3 years ago
5 0

Answer:

D. x = 0.5

Step-by-step explanation:

A graphing calculator is the quickest way to get to an answer here.

 f(x) = g(x) for x = 0.5

__

We can find the y-intercepts of the two functions to be ...

 f(0) = -3

 g(0) = -2

We know the x-intercept of g(x) is x=4. The x-intercept of f(x) will be a value less than 1, because f(1) = 1. (The function crosses the x-axis between x=0 where f(x) < 0 and x=1, where f(x) > 0.)

Considering these intercept points, we know the value of x for f(x)=g(x) will be between x=0 and x=1. There is only one answer choice in that interval:

 x = 0.5

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decimal form:
6.5-4-1.5x-2.25
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Mia climbs 5/8 of the height of the rock wall. Lee climbs 4/5 of Mia's distance. What fraction of the wall does Lee climb?
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Evaluate the function for an input value of 3. f (x) = -4x^2 – 3x – 5
Lina20 [59]

Answer:

  • -50

Step-by-step explanation:

<u>Function given:</u>

  • f(x) = -4x² – 3x – 5

Evaluate the function for an input value of 3

<u>Input value is x = 3, output value is:</u>

  • f(3) = -4(3²) – 3(3) – 5 = -4(9) - 9 - 5 = -36 - 14 = -50
  • f(3) = -50
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The Golden Rectangle can be found in the modern world<br> TRUE or FALSE
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3 years ago
A circle has a diameter with endpoints at (6, 5) and (8, 5). Write the equation for the circle.
mario62 [17]

Answer:

(x-7)^2+(y-5)^2=1

Step-by-step explanation:

The two things that are required to formulate the equation of the circle is the center coordinate and the radius of the circle!

<u>Center of the circle:</u>

  • The center of the circle always lies at the midpoint of the endpoints of its diameter: Let's call the endpoints A(6,5) and B(8,5).

Using the midpoint formula we'll get:

(x_m, y_m) = \left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

(x_m, y_m) = \left(\dfrac{6+8}{2},\dfrac{5+5}{2}\right)

(x_m, y_m) = (7,5)

This is the center coordinate of our circle.

<u>Radius: </u>

The radius of the circle is the distance from the center of the circle to any of the endpoints of the diameter (A or B)

We can use the distance formula:

r = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}

r = \sqrt{(x_1-x_m)^2+(y_1-y_m)^2}

r = \sqrt{(6-7)^2+(5-5)^2}

r = \sqrt{1^2}

r = 1

<u>Equation of the circle: </u>

The equation is written as:

(x-a)^2+(y-b)^2=r^2

here, (a,b) are the center points of the circle

in our case this is (a,b)=(x_m,y_m)=(7,5)

and r = 1

(x-7)^2+(y-5)^2=1^2

(x-7)^2+(y-5)^2=1

This is the equation of the circle!

3 0
3 years ago
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