$\stackrel{\textit{\LARGE Line A}}{(\stackrel{x_1}{-8}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{-5}~,~\stackrel{y_2}{4})} ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{4}-\stackrel{y1}{5}}}{\underset{run} {\underset{x_2}{-5}-\underset{x_1}{(-8)}}} \implies \cfrac{4 -5}{-5 +8}\implies -\cfrac{1}{3} \\\\[-0.35em] ~\dotfill$

$\stackrel{\textit{\LARGE Line B}}{(\stackrel{x_1}{0}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{-1})} ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-1}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{4}-\underset{x_1}{0}}} \implies \cfrac{-1 -1}{4 +0}\implies -\cfrac{1}{2}$

keeping in mind that perpendicular lines have negative reciprocal slopes, and that parallel lines have equal slopes, well, those two slopes above aren't either, so since they're neither, and they're different, that means that lines A and B intersect.

8 0

2 years ago

2. You plan to replace the carpeting in the room shown. What is the

RSB [31]

Answer:

$198\ ft^2$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that the area of the room is equal to the area of a rectangle plus the area of a trapezoid

step 1

Find out the area of the rectangle

$A_1=(18)(9)=162\ ft^2$

step 2

Find out the area of the trapezoid

$A_2=\frac{1}{2} (9+3)(6)=36\ ft^2$

step 3

Sum the areas

$A=A_1+A_2$

substitute the values

$A=162++36=198\ ft^2$

5 0

4 years ago

Read 2 more answers

Which is equivalent to (9y2 – 4x)(9y2 + 4x), and what type of special product is it?

QveST [7]

This is an example of the difference of squares.

$a^2 - b^2 = (a-b)(a+b)$

So to find the product of (9y² – 4x)(9y² + 4x), we use the formula for the difference of squares.

 $(9y^2 - 4x)(9y^2 + 4x)\\\\=(9y^2)^2 -(4x)^2\\\\=\boxed{\bf{81y^4 - 16x^2}}$

7 0

4 years ago

Can someone plz help me

ANEK [815]

Answer:

Step-by-step explanation:

8 0

3 years ago