9514 1404 393
Answer:
1.63 cm (across the centerline from release)
Step-by-step explanation:
If we assume time starts counting when we release the weight from its fully-extended downward position, then the position at 1.15 seconds can be found from ...
h(t) = -7cos(2πt/4)
h(1.15) = -7cos(π·1.15/2) = -7(-0.233445) ≈ 1.63412 . . . cm
That is, 1.15 seconds after the weight is released from below the resting position, it will be 1.63 cm above the resting position.
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If it is released from <em>above</em> the resting position, it will be 1.63 cm <em>below</em> the resting position at t=1.15 seconds.
Answer:
We are given a equation as:
5log(x+3)=5
We are asked to find a graph that is used to solve the above equation.
We can write the given equation as:
we will divide both side of the equation by 5 to obtain:
log(x+3)=1
Now we have to determine which graph represents the function:
y=log(x+3)
since we know that when x=-2.
y=log(-2+3)=log(1)=0
Hence, the graph should pass through (-2,0).
Hence, the graph that satisfies this is attached to the answer.
Step-by-step explanation:
The answer to the problem is -25
Answer:
D) 12.56
Step-by-step explanation:
The radius is 2
C=2 3.14 r
= 12.56
Answer:
33.92
Step-by-step explanation:
